在多個條件下使用多個JOIN

Question

我嘗試使用多個幫助表來顯示計時器的狀態。 （使用php的瀏覽器） 幫助器表格用於在語言之間切換。

這裏定時器類型輔助表：

+-------------+------+------------------+ 
| lfdLanguage | Type | TText   | 
+-------------+------+------------------+ 
|   0 | 0 | Puls    | 
|   0 | 1 | steigende Flanke | 
|   0 | 2 | fallende Flanke | 
|   1 | 0 | Pulse   | 
|   1 | 1 | rissing edge  | 
|   1 | 2 | falling edge  | 
+-------------+------+------------------+ 

和日活躍：

+-------------+--------+--------+ 
| lfdLanguage | Active | ACText | 
+-------------+--------+--------+ 
|   0 |  0 | _  | 
|   0 |  1 | X  | 
|   1 |  0 | _  | 
|   1 |  1 | X  | 
+-------------+--------+--------+ 

我通常使用相等連接，但在這裏我想顯示的天后地位（即RunMonday，...）使用相同的輔助表。

使用下面的語句沒有AND WHERE HTT.lfdLanguage = 0工作正常。

但是用where聲明我不能exexute。我得到一個錯誤：

('ERROR 1064 (42000): .....')

SELECT DISTINCT 
    T.lfdTimer, 
    T.Active, 
    T.Name, 
    T.Type,   HTT.TText, 
    T.RunMonday, HTDA1.ACText, 
    T.RunTuesday, HTDA2.ACText, 
    T.RunWednesady, HTDA3.ACText, 
    T.RunThursday, HTDA4.ACText, 
    T.RunFriday, HTDA5.ACText, 
    T.RunSaturday, HTDA6.ACText, 
    T.RunSunday, HTDA7.ACText 
FROM 
    Timer T 
INNER JOIN HelpTimerType  HTT ON (T.Type   = HTT.Type  AND WHERE HTT.lfdLanguage = 0); 
LEFT JOIN HelpTimerDayActive HTDA1 ON (T.RunMonday = HTDA1.Active) 
LEFT JOIN HelpTimerDayActive HTDA2 ON (T.RunTuesday = HTDA2.Active) 
LEFT JOIN HelpTimerDayActive HTDA3 ON (T.RunWednesady = HTDA3.Active) 
LEFT JOIN HelpTimerDayActive HTDA4 ON (T.RunThursday = HTDA4.Active) 
LEFT JOIN HelpTimerDayActive HTDA5 ON (T.RunFriday = HTDA5.Active) 
LEFT JOIN HelpTimerDayActive HTDA6 ON (T.RunSaturday = HTDA6.Active) 
LEFT JOIN HelpTimerDayActive HTDA7 ON (T.RunSunday = HTDA7.Active) 
; 

任何想法如何包括語言選擇到JOIN的？

所有幫助表示讚賞。 感謝

Answer 1

where子句來畢竟加入：

SELECT DISTINCT 
    T.lfdTimer, 
    T.Active, 
    T.Name, 
    T.Type,   HTT.TText, 
    T.RunMonday, HTDA1.ACText, 
    T.RunTuesday, HTDA2.ACText, 
    T.RunWednesady, HTDA3.ACText, 
    T.RunThursday, HTDA4.ACText, 
    T.RunFriday, HTDA5.ACText, 
    T.RunSaturday, HTDA6.ACText, 
    T.RunSunday, HTDA7.ACText 
FROM 
    Timer T 
INNER JOIN HelpTimerType  HTT ON (T.Type   = HTT.Type) 
LEFT JOIN HelpTimerDayActive HTDA1 ON (T.RunMonday = HTDA1.Active) 
LEFT JOIN HelpTimerDayActive HTDA2 ON (T.RunTuesday = HTDA2.Active) 
LEFT JOIN HelpTimerDayActive HTDA3 ON (T.RunWednesady = HTDA3.Active) 
LEFT JOIN HelpTimerDayActive HTDA4 ON (T.RunThursday = HTDA4.Active) 
LEFT JOIN HelpTimerDayActive HTDA5 ON (T.RunFriday = HTDA5.Active) 
LEFT JOIN HelpTimerDayActive HTDA6 ON (T.RunSaturday = HTDA6.Active) 
LEFT JOIN HelpTimerDayActive HTDA7 ON (T.RunSunday = HTDA7.Active) 
WHERE HTT.lfdLanguage = 0 
; 

Answer 2

從內部聯接取出

WHERE 

，這是錯誤的語法。