獲得{天}變量與笨日曆

Question

在我笨日曆我有這個模板值（從CodeIgniter用戶指南拍攝）：

{table_open}<table border="0" cellpadding="0" cellspacing="0" width="500" id="tabellaPrenotazioni">{/table_open} 
{heading_row_start}<tr>{/heading_row_start} 
{heading_previous_cell}<th><a href="{previous_url}">&lt;&lt;</a></th>{/heading_previous_cell} 
{heading_title_cell}<th colspan="{colspan}">{heading}</th>{/heading_title_cell} 
{heading_next_cell}<th><a href="{next_url}">&gt;&gt;</a></th>{/heading_next_cell} 

{heading_row_end}</tr>{/heading_row_end} 

{week_row_start}<tr>{/week_row_start} 
{week_day_cell}<td>{week_day}</td>{/week_day_cell} 
{week_row_end}</tr>{/week_row_end} 

{cal_row_start}<tr class="rigaGiorni">{/cal_row_start} 
{cal_cell_start}<td class="cellaGiorno">{/cal_cell_start} 

{cal_cell_content}<a href="{content}">{day}</a>{/cal_cell_content} 
{cal_cell_content_today}<div class="highlight"><a href="{content}">{day}</a></div>{/cal_cell_content_today} 

{cal_cell_no_content}{day}{/cal_cell_no_content} 
{cal_cell_no_content_today}<div class="highlight"><b>{day}</b></div>{/cal_cell_no_content_today} 

{cal_cell_blank}&nbsp;{/cal_cell_blank} 

{cal_cell_end}</td>{/cal_cell_end} 
{cal_row_end}</tr>{/cal_row_end} 

{table_close}</table>{/table_close} 

我需要通過編程出頭添加到每一天，根據該天它是，所以我需要在PHP變量中保存{day}值。我能怎麼做？

Answer 1

我看到日曆代替它圖書館。我認爲做到這一點的唯一方法是創建一個擴展日曆的庫，並在generate（）方法中進行更改。

Answer 2

解析的{day}相同echo $day;，這樣你就可以基本上與

echo $day + $something; 

或者任何你願意，你可以隨時與PHP變量，而不是偲那些工作