while循環在Java結束條件

Question

我想完成從一個在線Java教程的任務，我目前在關於While循環的問題。這是我的代碼：

import java.util.Scanner; 

public class bird { 
    public static void main(String[] args){ 
     Scanner bucky = new Scanner(System.in); 
     final String end = "END"; 
     String bird; 
     int amount; 

     System.out.println("What bird did you see in your garden? "); 
     bird = bucky.nextLine(); 

     while(!(bird.equals(end))){ 
      System.out.println("How many were in your garden? "); 
      amount = bucky.nextInt(); 

     } 
    } 
} 

我的問題是代碼意味着如果最終是由用戶，因此需要在While循環外部輸入的終止。但是如果沒有它在循環內部，它不會重複提出更多類型鳥類的問題。是否有辦法在循環中獲得第一個「你看到的是什麼鳥？」，同時如果滿足結束條件，還有退出循環的條件？

Answer 1

一種方式做到這一點（見代碼註釋）：

public static void main(String[] args){ 
    Scanner bucky = new Scanner(System.in); 
    final String end = "END"; 
    String bird; 
    int amount; 

    while(true){ // loop "forever" 
     System.out.println("What bird did you see in your garden? "); 
     bird = bucky.nextLine(); 
     if (end.equals(bird)) { // break out if END is entered 
      break; 
     } 

     System.out.println("How many were in your garden? "); 
     amount = bucky.nextInt(); 
     bucky.nextLine(); // consume the newline character after the number 

     System.out.println("we saw " + amount + " of " + bird); // for debugging 
    } 
} 

Answer 2

試試這個快速解決方案：

import java.util.Scanner; 

public class Bird { 
    public static void main(String[] args){ 

     Scanner bucky = new Scanner(System.in); 
     System.out.println("What bird did you see in your garden? "); 

     while(!(bucky.nextLine().equalsIgnoreCase("END"))){ 
      System.out.println("How many were in your garden? "); 
      bucky.nextInt(); 
      System.out.println("What bird did you see in your garden? "); 
      bucky.nextLine(); 
     } 
    } 
}