list1 = ["experience","as","a","java","developer"]
list2 = ["B","O","O","B","I"]
list3 = ["java","developer"]
number = 0
print(list2)
for i in list1:
for j in list3:
if(i!=j):
for l in range(number,len(list2)):
list2[number] = "O"
number += 1
print(list2)
這裏"B"
表示「experience」,"O"
表示「as」等等。Python:我需要以下程序的一些建議
預期輸出:
["O","O","O","B","I"]
我的輸出:
["O","O","O","O","O"]
你想設置o根據該單詞是否在list3中找到,但是您多次設置多個元素,它們是list2中的ne元素。 – stark
我要求(i!= j)意味着(經驗!= java)等等,如果這是真的,那麼list2索引應該替換爲「O」,而不是i [0]到j [0] – Shireesh