1
我wp_places定製表,我得到這個當我打印陣列:WordPress的MySQL的結果資源無效
[0] => stdClass Object
(
[home_location] => 24
)
[1] => stdClass Object
(
[home_location] => 29
)
現在我想爆這樣的方式(24,29)的價值,但在我的代碼我收到此錯誤:
<b>Warning</b>: mysql_fetch_array(): supplied argument is not a valid MySQL result resource
我的代碼
$getGroupType = $_POST['parent_category'];
$result = $wpdb->get_results("SELECT home_location FROM wp_places WHERE blood_group LIKE '".$getGroupType."%'");
$bgroup = Array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$bgroup[] = implode(',',$row);
}
echo implode(',',$bgroup);
條
任何意見或建議?謝謝。