構建陣列，用單引號包含多個值，而分隔每個用逗號

Question

我想我最終的結果看起來是這樣的：

Vendor1 => 'description1,description2,description3', 
Vendor2 => 'description4,description5,description6' 

我現在有這樣的事情：

if(mssql_num_rows($execute)){ 
    while($row = mssql_fetch_array($execute)){ 
     $dropdown[$row['VendorName']] .= "'" . $row['Transaction Description'] . "',"; 
    } 
} 

但是這給了我：

["Harland Financial Solutions"]=> 
    string(54) "'Software-implemention/license/support','sfw support'," 

Answer 1

好像你可以只刪除尾隨的逗號並刪除單引號。

if(mssql_num_rows($execute)){ 
    while($row = mssql_fetch_array($execute)){ 
     $dropdown[$row['VendorName']] .= $row['Transaction Description']."," 
    } 
    foreach($dropdown as $vendor => &$descriptions) 
     $descriptions = substr($descriptions, 0, -1); 
} 

Answer 2

在while循環結束後，使用PHP函數$string = substr($string, 0, -1)。它將返回一個比原始字符短一個字符的字符串（如果您正確填寫示例）。結果是最後一個逗號被切斷的字符串。有關substr()的文檔可以在PHP manual中找到。

if(...){ 
    while(...){ 
     ... 
     foreach($dropdown as &$string) 
     $string = substr($string, 0, -1); 
    } 
} 

Answer 3

. 
. 
. 
$dropdown[$row['VendorName']] .= $row['Transaction Description'] . ","; 
. 
. 
. 

像

foreach ($dropdown as $vendor=>&$data) 
$data=mb_substr($data,0,-1);//to remove the last , that you don't need