在Oracle SQL

Question

我想在2代表在這裏給定的ID進行刪除操作使用遊標是須藤代碼

declare 
    cursor del_id is 
    select person_id from table_1 where termination is true 

begin 
    for id_x in del_id 
    delete from table_X where id=id_x 
    delete from tabele_Y where id=id_x 

如何做到這一點？我不能直接使用我的光標，請幫忙。 我只是嘗試打印本人身份證

begin 

    for id in del_id 
    LOOP 
    dbms_output.put_line(id); 
    END LOOP; 
end; 

收到此錯誤

Error report - 
ORA-06550: line 11, column 3: 
PLS-00306: wrong number or types of arguments in call to 'PUT_LINE' 

Answer 1

若要從遊標打印值，你需要明確寫入你想要的列; dbms_output.put_line無法處理可能包含具有不同類型的許多列的行，因此您需要將它傳遞給一個字符串。

SQL> declare 
    2  cursor del_id is select 1 as one, 2 as two from dual; 
    3 begin 
    4 FOR id IN del_id 
    5 LOOP 
    6  dbms_output.put_line(id.one || ' - ' || id.two); 
    7 END LOOP; 
    8 end; 
    9/
1 - 2 

PL/SQL procedure successfully completed. 

如果你需要在某些語句中使用的值從遊標，在你的問題中DELETE，你需要做的是相同的，通過明確地寫在列名;例如：

declare 
    cursor del_id is select 1 as one, 2 as two from dual; 
begin 
    FOR id IN del_id 
    LOOP 
    delete from someTable where someColumn = id.one; 
    END LOOP; 
end; 

Answer 2

你不需要光標：

BEGIN 
    DELETE FROM table_X 
    WHERE id IN (select person_id from table_1 where termination is true); 

    DELETE FROM table_Y 
    WHERE id IN (select person_id from table_1 where termination is true); 
END; 
/

你也可以使用一個集合：

CREATE TYPE id_type IS TABLE OF INTEGER; 
/

DECLARE 
    ids id_type; 
BEGIN 
    SELECT person_id 
    BULK COLLECT INTO ids 
    FROM table_1 
    WHERE termination is true; 

    DELETE FROM table_X 
    WHERE id MEMBER OF ids; 

    DELETE FROM table_Y 
    WHERE id MEMBER OF ids; 
END; 
/