Laravel Eloquent爲列表過濾器名稱和用戶鏈接

Question

我使用過濾器從URL過濾學校，我需要向用戶顯示這些過濾器的鏈接。那麼，實際上我只需要向用戶展示使用後它們不返回空結果的過濾器。我試着用範圍和關係，我有這個錯誤：

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'specialties.school_id' in 'where clause' (SQL: select `id`, `name` from `specialties` where ((select count(*) from `schools` where `specialties`.`school_id` = `schools`.`id` and `specialties` like %""%) >= 1)) 

對我來說，我需要過濾的特色，區，直轄市，城市學校等。這是我的例子辦學模式：

<?php 

class School extends Eloquent { 
    protected $table = 'schools'; 

    public function scopeWhereSpecialties($query, $specialties) 
    { 
     if(!is_array($specialties)) 
     { 
      $specialties = [$specialties]; 
     } 

     return $query->where(function($q) use ($specialties) 
     { 
      foreach($specialties as $specialty){ 
       $q->where('specialties', 'like', '%"'.$specialty.'"%'); 
      } 
     }); 
    } 

    // I just delete other scopes to shorten the code 

    public function listSchoolsEndUser($filters) 
    { 
     $schools_data = School::query(); 

     foreach($filters as $filter => $value) 
     { 
      call_user_func(array($schools_data, 'where' . studly_case($filter)), $value); 
     } 

     return $schools_data->paginate(12); 
    } 

    public function listFilters($filters) 
    { 
     $specialties_filters = Specialty::select('id', 'name')->whereFilterAvailable($filters)->get()->toArray(); 

     return $specialties_filters; 
    } 
} 

而且還有我的例子專業模式：學校

<?php 

class Specialty extends Eloquent { 
    protected $table = 'specialties'; 

    public function scopeWhereFilterAvailable($query, $filters) 
    { 
     $specialty = $this->id; 
     return $query->where(function($q) use ($specialty, $filters) 
     { 
      $q->whereHas('school', function($q) use ($specialty, $filters) { 
       $q->where('specialties', 'like', '%"'.$specialty.'"%'); 
      }); 
     }); 
    } 

    public function school(){ 
     return $this->belongsTo('School'); 
    } 
} 

表結構similat到：

____________________________________ 
| id | name | specialties  | 
|____|_________|___________________| 
| 1 | example | ["1","2","3","4"] | 
|____|_________|___________________| 

而且表的特色結構similat到：

________________ 
| id | name | 
|____|_________| 
| 1 | example | 
|____|_________| 

Answer 1

的問題是，與select('id', 'name')您限制查詢，只有那些屬性，因此school_id不可用。你應該包括你（和你relationshipos）所需要的所有列：

$specialties_filters = Specialty::select('id', 'name', 'school_id')->whereFilterAvailable($filters)->get()->toArray(); 

也許lists()是一種選擇這裏。它創建了一個數組一個屬性作爲鍵和其他的價值：

$specialties_filters = Specialty::whereFilterAvailable($filters)->lists('name', 'id');