得到正確的輸出

Question

Select A.SubscriberKey, A.EventDate,B.CreatedDate 
From _Click A 
JOIN _ListSubscribers B 
ON A.SubscriberKey = B.SubscriberKey 
Where B.ListID = '10630' AND B.CreatedDate > (Select DATEADD(day,-180,getdate())) AND A.EventDate IS NULL 
Group By A.SubscriberKey,B.CreatedDate, A.EventDate 

目前需要輸入的SQL語句，正在返回任何內容。我想要返回訂閱者SubscriberKey（這是他們的電子郵件），EventDate（點擊發生的日期）以及他們沒有點擊任何內容時添加的日期（CreatedDate）。任何人都可以幫助我指出正確的方向嗎？感謝大家！

Answer 1

我沒有看到一個GROUP BY的目的，在這種情況下。你沒有做任何聚合。

我相信這會給你找到的結果。

select SubscriberKey, 
     null as EventDate, 
     CreatedDate 
    from _ListSubscribers ls 
where ListID='10630' 
    and CreatedDate > DateAdd(day, -180, getdate()) 
    and not exists(select 1 from _Click c where c.SubscriberKey = B.SubscriberKey) 

以下使用外連接的查詢應該給出相同的結果，它與您的原始查詢更類似。

select ls.SubscriberKey, 
     c.EventDate, 
     ls.CreatedDate 
    from _ListSubscribers ls 
    left outer join _Click c 
    on c.SubscriberKey = ls.SubscriberKey 
where ListID='10630' 
    and CreatedDate > DateAdd(day, -180, getdate()) 
    and c.EventDate is null 

Answer 2

嘗試：

SELECT A.SubscriberKey, A.EventDate, B.CreatedDate 
FROM _Click A, _ListSubscribers B 
WHERE A.SubscriberKey(+) = B.SubscriberKey 
AND B.ListID = '10630' 
AND B.CreatedDate > (Select DATEADD(day,-180,getdate())) 
AND nvl(A.EventDate,null) IS NULL 
GROUP BY A.SubscriberKey,B.CreatedDate, A.EventDate