Mysql的集團通過功能

Question

這是我的表：

Id customer email  timestamp    store_id 
1 1  abc@xx.com 2014-04-11 17:06:21 5416 
2 0  xyz@xy.com 2014-04-11 15:05:23 5416 
3 1  abc@xx.com 2014-04-11 17:55:34 5416 
4 2  bca@bc.com 2014-04-11 17:55:34 5416 

和我的查詢是：

SELECT *, count(*) as total FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` 
GROUP BY email) AND store_id='5416' GROUP BY email 

0在customer列中的值表示訪客和超過0意味着客戶ID。如果customer爲0，則我想通過email進行分組，其他分組由customer進行分組。這怎麼可能？

Answer 1

嘗試像這樣

SELECT *, count(*) as total 
FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` GROUP BY email) 
AND 
store_id='5416' 
GROUP BY 
case when customer=0 then customer else email end 

Answer 2

，我認爲這會工作：

SELECT *, count(*) as total 
FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` GROUP BY email) 
AND 
store_id='5416' 
GROUP BY 
IF(customer=0,email,customer)