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我想從IMDB自動添加提取的流派到我的類別。我讓JSON代碼爲我做這個。獲取未捕獲TypeError:無法使用'in'運算符搜索'長度'
$('input[name=Checkbx]').click(function() {
var coc = $('input[name=Checkbx2]').get(0).value;
// Send Request
$.getJSON("http://www.omdbapi.com/?i=" + coc + "&plot=short&r=json", function(data) {
var valDir = "";
var valWri = "";
var valAct = "";
$.each(data, function(key, val) {
$('input[name=' +key+ ']').val(val);
if(key == "Director"){
valDir+= " "+val+",";
}
if(key == "Genre"){
var genr = "";
$.each(data.Genre, function(key, val) {
genr += "" + val + ", ";
genr1 = val;
$('input[name=newcategory]').val(genr1);
$('#category-add-submit').trigger('click');
$('#category-add-submit').prop("disabled", false);
$('input[name=newcategory]').val("");
});
$('input[name=' +key+ ']').val(genr);
}
if(key == "Actors"){
valAct+= " "+val+",";
}
if(key == "Year"){
$('#new-tag-<?php echo get_option('year'); ?>').val(val);
}
if(key == "Country"){
$('#new-tag-movie-country').val(val);
}
});
$('#new-tag-<?php echo get_option("director"); ?>').val(valDir);
$('#new-tag-<?php echo get_option("actor"); ?>').val(valAct);
});
});
爲了記錄:我使用omdbapi.com API從IMDB得到的數據和測試我的電影ID爲tt0111161
和JSON輸出是:
{"Title":"The Shawshank Redemption","Year":"1994","Rated":"R","Released":"14 Oct 1994","Runtime":"142 min","Genre":"Crime, Drama","Director":"Frank Darabont","Writer":"Stephen King (short story \"Rita Hayworth and Shawshank Redemption\"), Frank Darabont (screenplay)","Actors":"Tim Robbins, Morgan Freeman, Bob Gunton, William Sadler","Plot":"Two imprisoned men bond over a number of years, finding solace and eventual redemption through acts of common decency.","Language":"English","Country":"USA","Awards":"Nominated for 7 Oscars. Another 14 wins & 20 nominations.","Poster":"http://ia.media-imdb.com/images/M/[email protected]_V1_SX300.jpg","Metascore":"80","imdbRating":"9.3","imdbVotes":"1,610,411","imdbID":"tt0111161","Type":"movie","Response":"True"}
,一切工作正常。我的意思是演員,導演和演員都是自動添加的。我的問題是與流派。
我得到這個錯誤:
Uncaught TypeError: Cannot use 'in' operator to search for 'length' in Crime, Drama
我的JQuery的版本是2.2.1。我怎樣才能解決這個問題?
非常感謝。它的作品就像一個魅力:D ... 另一個問題....例如,我想用另一個字代替這個功能中的「犯罪」..我怎麼能做到這一點? –