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我有這樣的事情:遞歸內加入與鄰接
CREATE TABLE categories (
id varchar(250) PRIMARY KEY,
name varchar(250) NOT NULL,
parentid varchar(250)
);
CREATE TABLE products (
id varchar(250) PRIMARY KEY,
name varchar(250) NOT NULL,
price double precision,
category varchar(250) NOT NULL
);
INSERT INTO categories VALUES ('1', 'Rack', '');
INSERT INTO categories VALUES ('2', 'Women', '1');
INSERT INTO categories VALUES ('3', 'Shorts', '2');
INSERT INTO products VALUES ('1', 'Jean', 2.99, '3');
INSERT INTO products VALUES ('2', 'Inflatable Boat', 5.99, '1');
現在,如果我想看到的產品的總價格爲每個類別,我可以做這樣的事情:
SELECT
categories.name,
SUM(products.price) AS CATPRICE
FROM
categories,
products
WHERE products.category = categories.id
GROUP BY categories.name
;
將會產生輸出:
name | catprice
--------+----------
Rack | 5.99
Shorts | 2.99
(2 rows)
但是請注意,「短褲」是「機架」的祖先。我想要一個查詢,將產生這樣的輸出:
name | catprice
--------+----------
Rack | 8.98
(1 row)
讓所有的產品價格是根類別下加在一起。類別表中有多個根類別;爲簡單起見,只有一個。
這是我迄今:
-- "nodes_cte" is the virtual table that is being created as the recursion continues
-- The contents of the()s are the columns that are being built
WITH RECURSIVE nodes_cte(name, id, parentid, depth, path) AS (
-- Base case?
SELECT tn.name, tn.id, tn.parentid, 1::INT AS depth, tn.id::TEXT AS path FROM categories AS tn, products AS tn2
LEFT OUTER JOIN categories ON tn2.CATEGORY = categories.ID
WHERE tn.parentid IS NULL
UNION ALL
-- nth case
SELECT c.name, c.id, c.parentid, p.depth + 1 AS depth, (p.path || '->' || c.id::TEXT) FROM nodes_cte AS p, categories AS c, products AS c2
LEFT OUTER JOIN categories ON c2.CATEGORY = categories.ID
WHERE c.parentid = p.id
)
SELECT * FROM nodes_cte AS n ORDER BY n.id ASC;
我不知道我做了什麼錯。上面的查詢返回零結果。
使用此功能,我可以添加「p.price」並再次爲每個類別提供價格總計。但是,我仍然需要獲得根類別的總數(在這種情況下爲「Rack」),我不知道應該在哪裏放置SUM。 – user2057674 2013-02-10 22:24:23
@ user2057674 - 查看編輯 - 祝您好運! – sgeddes 2013-02-11 00:08:52
哇,謝謝!是的,我需要它。 – user2057674 2013-02-11 13:04:03