提取信息 - 安卓

Question

我收到了從C＃應用程序推送，響應如下所示（它是一個束）：

Bundle [ 
    { 
     google.sent_time=1472471614026, 
     gcm.notification.msgid=27, 
     google.message_id=0:1472471614038882%8e7302d58e7302d5, 
     gcm.notification.aps= 
     { 
      "badge":1, 
      "alert": 
      { 
       "action-loc-key":"alert action key", 
       "title":"The alert title", 
       "body":"The alert body" 
      } 
     }, 
     collapse_key=com.devise.push 
    } 
] 

我怎麼會去實現的標題和正文的警報？

我已經嘗試bundle.getString("gcm.notification.aps");

Answer 1

是的，你已經嘗試

bundle.getString("gcm.notification.aps"); 

這是correnct會給你充分的JSON字符串，所以你只需要解析JSON這樣

String res =bundle.getString("gcm.notification.aps"); 
    try { 
     JSONObject mJSONObject = new JSONObject(res); 
     String title =mJSONObject.getJSONObject("alert").getString("title"); 
     String action =mJSONObject.getJSONObject("alert").getString("action-loc-key"); 
     String body =mJSONObject.getJSONObject("alert").getString("body"); 
     Log.e(TAG, "MSG: " + title+ " :: " + action + " :: " + body); 

    }catch (JSONException e){ 
     e.printStackTrace(); 
    }