2012-05-24 83 views
0

我嘗試在Web服務器上發送JSON數據並通過此方法獲取響應。httpclient.execute到web服務器上的異常

public JSONObject postOnServer(JSONObject json) { 

    HttpResponse response; 
    JSONObject res = null; 

    HttpClient httpclient = new DefaultHttpClient(); 
    HttpConnectionParams.setConnectionTimeout(httpclient.getParams(), 10000); 
    HttpPost httpPost = new HttpPost(PATH); 

    try { 

     //StringEntity stringEntity = new StringEntity("json", String.valueOf(json)); 
     ByteArrayEntity postMessage = new ByteArrayEntity(json.toString().getBytes("UTF8")); 
     httpPost.setEntity(postMessage); 
     response = httpclient.execute(httpPost); 

     if (response.getStatusLine().getStatusCode() == 200) { 

      InputStream instream = response.getEntity().getContent(); 
      try { 
       res = new JSONObject(convertStreamToString(instream)); 
      } catch (JSONException e) { 
       // TODO Auto-generated catch block 
       Log.i("Response JSON", e.toString()); 
      } 

     } else { 

      res = new JSONObject(); 
      try { 
       res.put("error", "Unable to load page."); 
      } catch (JSONException e) { 
       // TODO Auto-generated catch block 
      } 

     } 
    } catch (IOException ex) { 

     Log.i("Connection.postOnServer", "1.try exception: "+ex); 
     res = new JSONObject(); 
     try { 
      res.put("error", "Synchronization is not enable: Connection has aborted."); 
     } catch (JSONException e) { 
      Log.i("Connection.postOnServer", "put exception: "+e); 
     } 

    } 

    return res; 
} 

但它總是與此異常

05-24 10:58:51.635: E/AndroidRuntime(4709): FATAL EXCEPTION: main 
05-24 10:58:51.635: E/AndroidRuntime(4709): android.os.NetworkOnMainThreadException 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at android.os.StrictMode$AndroidBlockGuardPolicy.onNetwork(StrictMode.java:1099) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at libcore.io.BlockGuardOs.connect(BlockGuardOs.java:84) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at libcore.io.IoBridge.connectErrno(IoBridge.java:138) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at libcore.io.IoBridge.connect(IoBridge.java:112) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:192) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:459) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at java.net.Socket.connect(Socket.java:842) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.conn.scheme.PlainSocketFactory.connectSocket(PlainSocketFactory.java:119) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:144) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:360) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 
05-24 10:58:51.635: E/AndroidRuntime(4709):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 

有別人的想法就行response = httpclient.execute(httpPost);結束,如何解決呢?口渴嘗試如果我使用catch(IOException),應用程序是destroyd。如果我使用catch(Exception)應用程序繼續執行而不執行任何操作。我應該怎麼做才能發送數據?

+1

http://stackoverflow.com/a/4822122/1251715同樣的問題 – Th0rndike

+0

[HonyComb和DefaultHttpClient(可能重複http://stackoverflow.com/questions/4821845/honycomb-and -defaulthttpclient) – Marijn

回答

2

Android不允許您在用戶界面線程上運行網絡請求。這是爲了阻止在執行時干擾接口的請求。您需要在單獨的線程中執行請求。這裏有一個例子:

new Thread(new Runnable() { 
    //Thread to stop network calls on the UI thread 
    public void run() { 
     //Request the HTML 
     try { 
      HttpParams httpParameters = new BasicHttpParams(); 
      HttpConnectionParams.setConnectionTimeout(httpParameters, TIMEOUT_CONNECTION); 
      HttpConnectionParams.setSoTimeout(httpParameters, TIMEOUT_SOCKET); 

      HttpClient client = new DefaultHttpClient(httpParameters); 
      HttpGet request = new HttpGet(getString(R.string.url)); 
      HttpResponse response = client.execute(request); 

      //Do something with the response 
     } 
     catch (IOException e) { 
      Log.e("Tag", "Could not get HTML: " + e.getMessage()); 
     } 
    } 
}).start(); 
+1

以及我如何從我所做的方法返回該響應? – Vaek

+0

你沒有。如果你返回了一個響應,這意味着調用方法必須等待響應,所以你可以不用線程。任何需要更新的更新,都需要在執行網絡調用的線程中完成。 –