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我有一個大的矩陣(15000行x 2500列)使用PyTables存儲並獲取如何遍歷行的列迭代。在documentation我只看到如何通過名稱手動訪問每行。如何使用PyTable迭代列名稱?
我有這樣的列:
- ID
- X20160730_Day10_123a_2
- X20160730_Day10_123b_1
- X20160730_Day10_123b_2
ID列值是像 '10692.RFX7',但所有其它的字符串單元格值是浮動。這種選擇的作品,我可以遍歷結果的行,但我看不出如何遍歷列,並檢查它們的值:
from tables import *
import numpy
def main():
h5file = open_file('carlo_seth.h5', mode='r', title='Three-file test')
table = h5file.root.expression.readout
condition = '(ID == b"10692.RFX7")'
for row in table.where(condition):
print(row['ID'].decode())
for col in row.fetch_all_fields():
print("{0}\t{1}".format(col, row[col]))
h5file.close()
if __name__ == '__main__':
main()
如果我只是重複「在排山坳」什麼也沒有發生。由於代碼的正上方,我得到一個堆棧:
10692.RFX7
Traceback (most recent call last):
File "tables/tableextension.pyx", line 1497, in tables.tableextension.Row.__getitem__ (tables/tableextension.c:17226)
KeyError: b'10692.RFX7'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "tables/tableextension.pyx", line 126, in tables.tableextension.get_nested_field_cache (tables/tableextension.c:2532)
KeyError: b'10692.RFX7'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "./read_carlo_pytable.py", line 31, in <module>
main()
File "./read_carlo_pytable.py", line 25, in main
print("{0}\t{1}".format(col, row[col]))
File "tables/tableextension.pyx", line 1501, in tables.tableextension.Row.__getitem__ (tables/tableextension.c:17286)
File "tables/tableextension.pyx", line 133, in tables.tableextension.get_nested_field_cache (tables/tableextension.c:2651)
File "tables/utilsextension.pyx", line 927, in tables.utilsextension.get_nested_field (tables/utilsextension.c:8707)
AttributeError: 'numpy.bytes_' object has no attribute 'encode'
Closing remaining open files:carlo_seth.h5...done
是,那部分很簡單。但是我有成千上萬的列,想迭代它們來檢查它們的值,並選擇性地打印列名和它們的值(如果它們落在一定範圍內)。手動訪問它們的名字不會有幫助。 – Jorvis
謝謝!編輯後,我看到你添加了迭代。我被困在想你可以從選定的行中訪問它。這工作。 – Jorvis