PHP preg_replace以$開頭的任何數字xxx by xxx

-1

我想用xxx替換文本中每個出現的$（任何數字）。例如，如果在文本中出現$ 923，那麼它應該是xxx。

模式我都試過

    $string = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. $350 remaining essentially unchanged. It was popularised in the 1960s with the release of $90 required Letraset sheets containing Lorem Ipsum passages, and more recently with desktop publishing software like Aldus PageMaker including versions of Lorem Ipsum."; 

        $pattern = '/^\$[0-9]+\.?[0-9]?[0-9]/i'; 

        $pattern = '/($\[0-9]+)/'; 

        $replacement = "xxx"; 
        echo preg_replace($pattern, $replacement, $string);

來源

2016-02-05 dr10

歡迎SO。請閱讀[我可以問哪些主題]（http://stackoverflow.com/help/on-topic）和[如何提出一個好問題]（http://stackoverflow.com/help/how-to - 問）和[完美的問題]（http://codeblog.jonskeet.uk/2010/08/29/writing-the-perfect-question/） SO是**不是免費的編碼或教程服務* *你必須表明你已經努力解決你自己的問題。 – RiggsFolly

試試這個 -

$s = "$434 dsvsv $567 fsdgjfb"; 

echo preg_replace('/\$\d+/', 'xxx', $s);

輸出

xxx dsvsv xxx fsdgjfb

來源

2016-02-05 12:14:14

謝謝！ :) – dr10

PHP preg_replace以$開頭的任何數字xxx by xxx

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