需要使用SQL查詢援助

Question

我有3個表，我試圖創建一個查詢：
表1（iuieEmployee） - >位置編號
表2（jbEmployeeH1BInfo） - >位置號碼，LCA號，開始日期
表3（jbEmployeeLCA） - > LCA數
表4（jbInternationsl） - >主人口統計表

我有一個查詢那裏只有1在每個表中記錄的是工作正常，但表2和3可以有多個記錄。我希望它能找到最近開始日期的記錄，並確認第三張表格中有匹配的LCA編號，第一張表格中有匹配的位置編號，並向我顯示不是這種情況的任何記錄。我怎樣才能做到這一點？我目前有：

SELECT DISTINCT jbInternational.idnumber, jbInternational.lastname, jbInternational.firstname, jbInternational.midname, 
      jbInternational.campus, jbInternational.universityid, jbInternational.sevisid, jbInternational.citizenship, 
      jbInternational.immigrationstatus, jbEmployeeH1BInfo.lcaNumber AS lcaNumber1, jbEmployeeLCA.lcaNumber AS lcaNumber2 

FROM (select jbEmployeeH1BInfo.idnumber, MAX(jbEmployeeH1BInfo.approvalStartDate) AS MaxDateStamp FROM [internationalservices].[dbo].jbEmployeeH1BInfo GROUP BY idnumber) my 
      INNER JOIN [internationalservices].[dbo].jbEmployeeH1BInfo WITH (nolock) ON my.idnumber=jbEmployeeH1BInfo.idnumber AND my.MaxDateStamp=jbEmployeeH1BInfo.approvalStartDate 
      INNER JOIN [internationalservices].[dbo].jbInternational WITH (nolock) ON jbInternational.idnumber=jbEmployeeH1BInfo.idnumber 
      inner join [internationalservices].[dbo].jbEmployeeLCA ON jbInternational.idnumber = jbEmployeeLCA.idnumber 

WHERE jbInternational.idnumber not in(

SELECT DISTINCT jbInternational.idnumber 

FROM (select distinct jbEmployeeH1BInfo.idnumber, MAX(jbEmployeeH1BInfo.approvalStartDate) AS MaxDateStamp 
      FROM [internationalservices].[dbo].jbEmployeeH1BInfo GROUP BY idnumber) my 
      INNER JOIN [internationalservices].[dbo].jbEmployeeH1BInfo WITH (nolock) ON my.idnumber=jbEmployeeH1BInfo.idnumber AND my.MaxDateStamp=jbEmployeeH1BInfo.approvalStartDate 
      INNER JOIN [internationalservices].[dbo].jbInternational WITH (nolock) ON jbInternational.idnumber=jbEmployeeH1BInfo.idnumber 
      inner join [internationalservices].[dbo].jbEmployeeLCA ON jbInternational.idnumber = jbEmployeeLCA.idnumber 
      AND jbEmployeeH1BInfo.lcaNumber = jbEmployeeLCA.lcaNumber) 

表模式：

create table iuieEmployee(idnumber int, POS_NBR varchar(8)); 
insert into iuieEmployee values(123456, '470V13'); 
insert into iuieEmployee values(123457, '98X000'); 
insert into iuieEmployee values(123458, '98X000'); 
insert into iuieEmployee values(123455, '98X000'); 

create table jbEmployeeH1BInfo (idnumber int, approvalStartDate smalldatetime, lcaNumber varchar(20), positionNumber varchar(200)); 
insert into jbEmployeeH1BInfo values (123456, 07/01/2012, '1-200-3000', '98X000'); 
insert into jbEmployeeH1BInfo values (123456, 07/30/2013, '1-200-4000', '470V13'); 
insert into jbEmployeeH1BInfo values (123457, 07/01/2012, '1-200-5000', '98X000'); 
insert into jbEmployeeH1BInfo values (123458, 07/01/2012, '1-200-6000', '98X000'); 
insert into jbEmployeeH1BInfo values (123455, 07/30/2014, '1-200-7000', '98X000'); 
insert into jbEmployeeH1BInfo values (123455, 07/01/2012, '1-200-8000', '470V13'); 

create table jbEmployeeLCA (idnumber int, lcaNumber varchar(20)); 
insert into jbEmployeeLCA values (123456, 1-200-3000); 
insert into jbEmployeeLCA values (123456, 1-200-4111); 
insert into jbEmployeeLCA values (123457, 1-200-5000); 
insert into jbEmployeeLCA values (123458, 1-200-6000); 
insert into jbEmployeeLCA values (123455, 1-200-7000); 
insert into jbEmployeeLCA values (123455, 1-200-8000); 

create table jbInternational(idnumber int); 
insert into jbInternational values(123456); 
insert into jbInternational values(123457); 
insert into jbInternational values(123458); 
insert into jbInternational values(123455); 

應該只返回1行：
123456，2013年7月30日， '1-200-4000'

但代替返回兩行：
123456，07/30/2013，'1-200-4000（不匹配1-200-4111）
123456，07/30/2013，'1-200-4000（不匹配1 -200-3000）
它不應該返回第二行，因爲具有-3000 lca編號的位置編號沒有最新的日期。

Answer 1

你的解釋很難理解。我想如果你能解釋得很好，那麼你可以自己編寫查詢。以下是我認爲你的意思：

員工包含主要記錄。

你想找到所有idnumbers這樣

• 的IDNumber是國際
• 的H1BInfo紀錄最近approvalStartDate沒有匹配的LCA記錄

的一個LCA數首先要做的是簡化H1BInfo表。我們只查找具有最新approvalStartDate的行。我們可以做的是通過劃分由IDNumber中和排序由approvalStartDate：

with rankedH1BInfo as (
    SELECT *, 
     ROW_NUMBER() OVER (PARTITION BY jbEmployeeH1BInfo.idnumber 
      ORDER BY jbEmployeeH1BInfo.approvalStartDate desc) as r 
    FROM [internationalservices].[dbo].jbEmployeeH1BInfo 
) 

讓我們只得到每個分區的第一行：

, MostRecentH1BInfo as (
    SELECT * FROM rankedH1BInfo 
    WHERE r = 1 
) 

現在我們可以做加盟找到好的都給：

, goodIDs as (
    SELECT i.idnumber 
    FROM [internationalservices].[dbo].jbInternational i WITH (NOLOCK) 
    JOIN [internationalservices].[dbo].jbEmployeeLCA l WITH (NOLOCK) on l.idnumber = i.idnumber 
    JOIN MostRecentH1BInfo h WITH (NOLOCK) on h.idnumber = i.idnumber 
    JOIN iuieEmployee e WITH (NOLOCK) on e.positionNumber = h.positionNumber 
    WHERE h.lcaNumber = l.lcaNumber 
) 

爲了把它放在一起，並得到的那些地方，這是錯誤的：

with rankedH1BInfo as (
    SELECT *, 
     ROW_NUMBER() OVER (PARTITION BY jbEmployeeH1BInfo.idnumber 
      ORDER BY jbEmployeeH1BInfo.approvalStartDate desc) as r 
    FROM [internationalservices].[dbo].jbEmployeeH1BInfo 
), MostRecentH1BInfo as (
    SELECT * FROM rankedH1BInfo 
    WHERE r = 1 
), goodIDs as (
    SELECT i.idnumber 
    FROM [internationalservices].[dbo].jbInternational i WITH (NOLOCK) 
    JOIN [internationalservices].[dbo].jbEmployeeLCA l WITH (NOLOCK) on l.idnumber = i.idnumber 
    JOIN MostRecentH1BInfo h WITH (NOLOCK) on h.idnumber = i.idnumber 
    JOIN iuieEmployee e WITH (NOLOCK) on e.positionNumber = h.positionNumber 
    WHERE h.lcaNumber = l.lcaNumber 
) 
SELECT DISTINCT jbInternational.idnumber, jbInternational.lastname, jbInternational.firstname, jbInternational.midname, 
     jbInternational.campus, jbInternational.universityid, jbInternational.sevisid, jbInternational.citizenship, 
     jbInternational.immigrationstatus, jbEmployeeH1BInfo.lcaNumber AS lcaNumber1, jbEmployeeLCA.lcaNumber AS lcaNumber2 
FROM (select jbEmployeeH1BInfo.idnumber, MAX(jbEmployeeH1BInfo.approvalStartDate) AS MaxDateStamp FROM [internationalservices].[dbo].jbEmployeeH1BInfo GROUP BY idnumber) my 
      INNER JOIN [internationalservices].[dbo].jbEmployeeH1BInfo WITH (nolock) ON my.idnumber=jbEmployeeH1BInfo.idnumber AND my.MaxDateStamp=jbEmployeeH1BInfo.approvalStartDate 
      INNER JOIN [internationalservices].[dbo].jbInternational WITH (nolock) ON jbInternational.idnumber=jbEmployeeH1BInfo.idnumber 
      inner join [internationalservices].[dbo].jbEmployeeLCA ON jbInternational.idnumber = jbEmployeeLCA.idnumber 
WHERE jbInternational.idnumber not in (select idnumber from goodIDs)