治療多發性分隔符分隔字段重複行

Question

我繼承了一個表（誰沒有，對吧？），有看起來像這樣的數據：

Item   |    Properties  |  Quantity 
-------------------------------------------------------------------- 
Shirt   | button-down,polo,sleeveless |   4,5,8 

在短期內，我想創建一個視圖，但最終我想將數據導出表中的一個新版本時，時間允許和有它更像是：

Item   |    Properties  |  Quantity 
-------------------------------------------------------------------- 
Shirt   |   button-down  |   4 
Shirt   |    polo   |   5 
Shirt   |    sleeveless  |   8 

從本質上講，採取多列組（我想象還會有其他的表那裏有更多的列比兩個具有這種行爲）已知是分隔符和bre將它們分爲不同的行？收集到的其他不同於此的行將在它們之間共享，如本例中的Item。這些類型之間的逗號數是統一的。

編輯：我以前在答案中給出的函數How to convert comma separated NVARCHAR to table records in SQL Server 2005?，這是目前我有：

select distinct data.item, tmptbl.[String] from 
    data cross apply [ufn_CSVToTable](data.properties, ',') tmptbl ... 

這工作在單柱背景，但應用該功能，第二列（數量在這種情況下）徹底會產生所有可能的性質和數量的組合，對吧？事實上，是的，當我嘗試時，確實導致了這種情況。看起來我需要一個光標或類似的符號來有效地分解成單獨的屬性行[i] |數量[我]，將嘗試和構建。這或者可能只是選擇數據並在應用程序端分割它。

Answer 1

使用從here分割字符串之一..

如果你確定屬性將始終有相同數量算作數量（我的意思是在性能3個價值觀和數量3個值），那麼您可以更換與內一個低於加入..

;With cte 
as 
(select t.item ,a1.item as 'Properties',row_number() over (order by (select null)) as rownum1 
from #test t 
cross apply 
[dbo].[SplitStrings_Numbers](proper,',') a1 
) 
,cte1 as 
(
select a2.item as quantity,row_number() over (order by (select null)) as rownum2 
from #test t 
cross apply 
[dbo].[SplitStrings_Numbers](quantity,',') a2 
) 
Select c.ite,c.Properties,c1.quantity 
from cte c 
full join 
cte1 c1 
on c.rownum1=c1.rownum2 

輸出：

item Properties quantity 
Shirt button-down 4 
Shirt polo   5 
Shirt sleeveless  8 

Answer 2

CREATE FUNCTION [dbo].[ReturnTableOfVarchars] 
    (@IDList varchar(8000)) 
    -- allow up to 256 varchar 
    RETURNS @IDTable table (RecordID varchar(256) NOT NULL) 
AS 
    BEGIN 
    DECLARE @IDListPosition int, 
     @ArrValue varchar(8000) 
    SET @IDList = COALESCE(@IDList,'') 
    IF @IDList<>'' 
     BEGIN 
     -- add a comma to end of list 
     SELECT @IDList = @IDList+',' 
     -- Loop through the comma delimited string list 
     WHILE PATINDEX('%,%',@IDList)<>0 
     BEGIN 
      -- find the position of the first comma in the list 
      SELECT @IDListPosition = PATINDEX('%,%',@IDList) 
      -- extract the string 
      SELECT @ArrValue = LEFT(@IDList, @IDListPosition - 1) 
      INSERT @IDTable (RecordID) VALUES(@ArrValue) 
      -- remove processed string 
      SELECT @IDList = STUFF(@IDList,1,@IDListPosition ,'') 
     END 
     END 
    RETURN 
    END 

使用：

declare @itemvalues varchar(100) ,@itemcount varchar(100) 
set @itemvalues='button-down,polo,sleeveless' 
SET @itemcount =' 4,5,8' 

select * from dbo.ReturnTableOfVarchars(@itemvalues) 
select * from dbo.ReturnTableOfVarchars(@itemcount) 

以上函數從字符串拆分值，你可以從選擇或更新根據您的過程中插入的值。

Answer 3

隨着他分離器和交叉的LP適用

Declare @YourTable table (item varchar(50),Properties varchar(50),Quantities varchar(50)) 
Insert into @YourTable values 
('Shirt','button-down,polo,sleeveless','4,5,8') 


Select A.item 
     ,B.Properties 
     ,B.Quantities 
From @YourTable A 
Cross Apply (Select Properties=A.Key_Value 
        ,Quantities=B.Key_Value 
       From (Select * from [dbo].[udf-Str-Parse](A.Properties,',')) A 
       Left Join (Select * from [dbo].[udf-Str-Parse](A.Quantities,',')) B on A.Key_PS=B.Key_PS 
) B 

返回

item Properties Quantities 
Shirt button-down 4 
Shirt polo   5 
Shirt sleeveless 8 

的UDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimeter varchar(10)) 
--Usage: Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',') 
--  Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ') 
--  Select * from [dbo].[udf-Str-Parse]('id26,id46|id658,id967','|') 
--  Select * from [dbo].[udf-Str-Parse]('hello world. It. is. . raining.today','.') 

Returns @ReturnTable Table (Key_PS int IDENTITY(1,1), Key_Value varchar(max)) 
As 
Begin 
    Declare @XML xml;Set @XML = Cast('<x>' + Replace(@String,@Delimeter,'</x><x>')+'</x>' as XML) 
    Insert Into @ReturnTable Select Key_Value = ltrim(rtrim(String.value('.', 'varchar(max)'))) FROM @XML.nodes('x') as T(String) 
    Return 
End