無法在PHP中使用用戶名和密碼登錄

Question

<?php 
//Get Session 
$getSession = isset($_SESSION['forum_user']) ? $_SESSION['forum_user'] : ""; 

//Login Script 
$postLoginBtn = isset($_POST['forum_login_submit']) ? $_POST['forum_login_submit'] : ""; 

if ($postLoginBtn == "Login") { 
    $user = isset($_POST['forum_user']) ? $_POST['forum_user'] : ""; 
    $pass = isset($_POST['forum_pass']) ? $_POST['forum_pass'] : ""; 
    $pass = md5($pass); 
    $query = mysql_query("SELECT * FROM admin_users WHERE user_name='{$user}' and password='{$pass}'"); 
    echo "SELECT * FROM admin_users WHERE user_name='{$user}' and user_password ='{$pass}'"; 
    $count = mysql_num_rows($query); 
    //echo $count; 
    if ($count == 1) { 
     $_SESSION['forum_user'] = $_POST['forum_user']; 
     header("Location:admin.php"); 
    } else { 
     echo "<script type='text/javascript'>"; 
      echo "alert('Entered username and password is not matched. Please try again!!');"; 
      echo "window.location='index.php';"; 
      echo "</script>"; 
    } 
} 

if ($getSession == "") { 
    ?> 
    <div id="loginContainer"> 
     <div id="loginDiv"> 
      <div id="loginHeadingDiv">LOGIN PANEL</div> 
      <div id="loginFieldsDiv"> 
       <form action="" method="post"> 
        <table id="loginTable"> 
         <tr> 
          <td>Username</td> 
          <td><input type="text" class="loginFields" name="forum_user" /></td> 
         </tr> 
         <tr> 
          <td>Password</td> 
          <td><input type="password" class="loginFields" name="forum_pass" /></td> 
         </tr> 
         <tr> 
          <td></td> 
          <td><input type="submit" id="loginSbmtBtn" value="Login" name="forum_login_submit" /></td> 
         </tr> 
        </table> 
       </form> 
      </div> 
     </div> 
    </div> 

    <?php 
} else { 
    echo "<script type='text/javascript'>"; 
    echo "alert('Kindly login to enter the admin area.');"; 
    echo "window.location='index.php';"; 
    echo "</script>"; 
} 
?> 

我想登錄，但我得到一個錯誤「警告：mysql_num_rows（）期望參數1是資源，布爾給定login.php第15行」; .T已經嘗試了很多，但無法解決請幫助我。

Answer 1

試試這個 - >

$res="write your select query here" ; 
    $result=mysql_query($res) or die("query fail to execute".mysql_error()); 
    $total=mysql_num_rows($result); 
    if($total<0){ 
    echo "no row found"; 
    } 
    else{ 
    while($row=mysql_fetch_array($result)) 
    { 
    // some code}