如何在MySql中使用Group By實現以下結果？

考慮下表：如何在MySql中使用Group By實現以下結果？

+------------+-----------+-------------+---------+------------+--------+-------------+ 
    | client_id | TradeDate | servicetype | SEGMENT | OrdChannel | orders | OrderAmount | 
    +------------+-----------+-------------+---------+------------+--------+-------------+ 
    |  1  | 20140611 | Type_1  | CASH | TT   |  1 |  39275 | 
    |  2  | 20150119 | Type_1  | CASH | DNT  |  2 |  11856.9 | 
    |  3  | 20150922 | Type_1  | FNO  | OTHER  |  1 |  854750 | 
    |  4  | 20151223 | Type_1  | CASH | TT   |  5 |  71075 | 
    |  5  | 20140529 | Type_1  | Offline | FNO  |  1 |   0 | 
    |  6  | 20160310 | Type_2  | CASH | WEB  |  2 |  8009.6 | 
    |  7  | 20150318 | Type_1  | Offline | FNO  |  2 |  432900 | 
    |  8  | 20150914 | Type_2  | CASH | WEB  |  2 |  15612 | 
    |  9  | 20160317 | Type_2  | FNO  | MINI  |  1 |  9000 | 
    |  10 | 20140421 | Type_1  | CASH | TT   |  8 |  17112.5 | 
    +------------+-----------+-------------+---------+------------+--------+-------------+

我被client_id和TradeDate想這組數據。因此最終數據集將包含每對<client-id, TradeDate>的每一行。我想計算從該數據如下特點：

對於每對中的每個類型的段，我想計算定單的總和和OrderAmount
類似地，對於每一個各類型OrdChannel的對，我想計算訂單總數和OrderAmount
最後，每個servicetype的計數即Type_1和Type_2。

因此最終的數據集將包含如下圖所示類似列：

+------------+-----------+-------------+---------+------------+--------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+ 
    | client_id | TradeDate | SEGMENT_CASH_orders_sum | SEGMENT_CASH_OrderAmount_sum.... | OrdChannel_TT_orders_sum | OrdChannel_TT_OrderAmount_sum.... | servicetype_Type_1_count | servicetype_Type_2_count | 
    +------------+-----------+-------------+---------+------------+--------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+-------------+

到目前爲止，我曾嘗試：

select clientsrno, TradeDate, SEGMENT, COUNT(orders) from orders group by clientsrno, TradeDate, SEGMENT;

，但它不是給單獨列SEGMENT_CASH-orders_sum等。

取而代之的輸出是：

+------------+-----------+---------+---------------+ 
    | clientsrno | TradeDate | SEGMENT | COUNT(orders) | 
    +------------+-----------+---------+---------------+ 
    |   44 | 20141209 | CASH |   23 | 
    |   44 | 20141211 | FNO  |   10 | 
    +------------+-----------+---------+---------------+

來源

2016-05-03 Sangram

爲什麼不提供想要的結果？ – Strawberry

你可以有很多總和（CASE .... END）做

這是一個suggestionfor的firts列

select client_di, TradeDate 
    sum (case SEGMENT 
     when 'CASH' then orders ELSE 0 END) as SEGMENT_CASH_orders_sum, 
    sum (case SEGMENT 
     when 'CASH' then OrderAmount ELSE 0 END) as SEGMENT_CASH_ordersAmount_sum, 
    sum (case SEGMENT 
     when 'FNO' then orders ELSE 0 END) as SEGMENT_FNO_orders, 
    sum (case SEGMENT 
     when 'FNO' then OrderAmount ELSE 0 END) as SEGMENT_FNO_ordersAmount_sum 
from my_table 
group by client_id, TradeDate

來源

2016-05-03 12:07:24 scaisEdge

嗨@scaisEdge，我嘗試了sum-case的各種版本，但得到一個語法錯誤。 – Sangram

對不起太多= ..我已經更新了答案 – scaisEdge

似乎我們也可以用=來寫。其實我們錯過了TradeDate之後的逗號（，）！：D非常感謝您的幫助。 – Sangram

比如，你可以這樣做：

SELECT clientsrno, TradeDate, SEGMENT, COUNT(orders), sumOrders.total FROM tabletest 
INNER JOIN (
    SELECT tabletest.tradeDate, SUM(orders) as total FROM tabletest 
    GROUP BY clientsrno, TradeDate, SEGMENT 
) sumOrders ON tableTest.tradeDate = sumOrders.tradeDate 
GROUP BY clientsrno, TradeDate, SEGMENT

然後重複你需要的每一筆款項的處理。

來源

2016-05-03 12:09:06 Grommy

如何在MySql中使用Group By實現以下結果？

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