我在Symfony組件上創建了一個框架。 http://symfony.com/doc/2.7/create_framework/index.html在Symfony控制器中訪問容器
我想訪問我的控制器中的容器,但我不知道如何做到這一點的OOP方式。
我目前正在通過global
訪問它,但我相信會有更好的方法來做同樣的事情。請參考我的代碼塊:
#services.yml file
services:
calendar.model.leapyear:
class: Calendar\Model\LeapYear
前端控制器文件
<?php
require_once __DIR__.'/../vendor/autoload.php';
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing;
use Symfony\Component\HttpKernel;
$request = Request::createFromGlobals();
$routes = include __DIR__ . '/../src/routes.php';
$container = include __DIR__ . '/../src/app/Container.php';
$context = new Routing\RequestContext();
$matcher = new Routing\Matcher\UrlMatcher($routes, $context);
$controllerResolver = new HttpKernel\Controller\ControllerResolver();
$argumentResolver = new HttpKernel\Controller\ArgumentResolver();
$framework = new Framework($matcher, $controllerResolver, $argumentResolver);
$response = $framework->handle($request);
$response->send();
LeapYearController文件
<?php
namespace Calendar\Controller;
use Controller;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
class LeapYearController extends Controller
{
protected $model;
public function indexAction(Request $request, $year)
{
$this->model = $this->container->get('calendar.model.leapyear');
if ($this->model->isLeapYear($year)) {
return new Response('Yep, this is a leap year!');
}
return new Response('Nope, this is not a leap year.');
}
}
基地控制器
<?php
namespace Controller;
use Symfony\Component\DependencyInjection\ContainerAware;
class Controller extends ContainerAware
{
protected $container;
public function __construct()
{
global $container;
$this->container = $container;
}
}
我基本上不想使用全局$容器,並試圖找到更好的方式來訪問我的LeapYear控制器中的容器 –