得到錯誤的PL/SQL的Oracle

Question

我在PL/SQL的新手，我有下面的代碼的問題：

ALTER TRIGGER secure_employees DISABLE; 

ALTER TABLE employees (ADD (exceed_avgsal VARCHAR2(3) DEFAULT 'NO' 
CONSTRAINT employees_exceed_avgsal_ck CHECK (exceed_avgsal IN ('YES', 'NO'))); 

CREATE OR REPLACE PROCEDURE check_avgsal IS 
    avgsal_exceeded employees.exceed_avgsal%type; 
    CURSOR emp_csr IS 
    SELECT employee_id, job_id, salary FROM employees FOR UPDATE; 
    e_resource_busy EXCEPTION; 
    PRAGMA EXCEPTION_INIT(e_resource_busy, -54); 

    FUNCTION get_job_avgsal(jobid VARCHAR2) RETURN NUMBER IS 
    avg_sal employees.salary%type; 
    BEGIN 
    SELECT (max_salary + min_salary)/2 
     INTO avg_sal 
     FROM jobs 
    WHERE job_id = jobid; 
    RETURN avg_sal; 
    END; 
BEGIN 
    FOR emprec IN emp_csr LOOP 
    avgsal_exceeded := 'NO'; 
    IF emprec.salary >= get_job_avgsal(emprec.job_id) THEN 
     avgsal_exceeded := 'YES'; 
    END IF; 
    UPDATE employees 
     SET exceed_avgsal = avgsal_exceeded 
    WHERE CURRENT OF emp_csr; 
    END LOOP; 
EXCEPTION 
    WHEN e_resource_busy THEN 
    ROLLBACK; 
    RAISE_APPLICATION_ERROR(-20001, 'Record is busy, try later.'); 
END check_avgsal; 

EXECUTE check_avgsal 

SELECT e.employee_id, e.job_id, (j.max_salary-j.min_salary/2) job_avgsal, e.salary, e.exceed_avgsal avg_exceeded 
FROM employees e, jobs j WHERE e.job_id = j.job_id and e.exceed_avgsal = 'YES'; 
COMMIT; 

我得到錯誤信息

PROCEDURE CHECK_AVGSAL compiled
Errors: check compiler log

如果有人可以幫助我，我會感激

Answer 1

你需要對自己的一條線/，該end chk_avgsal;和下一條語句，to run the PL/SQL block之間：

... 
END LOOP; 
EXCEPTION WHEN e_resource_busy THEN ROLLBACK; 
RAISE_APPLICATION_ERROR (-20001, 'Record is busy, try later.'); 
END check_avgsal; 
/

EXECUTE check_avgsal 
... 

你alter table語法是錯誤太：

ALTER TABLE employees ADD (exceed_avgsal VARCHAR2(3) DEFAULT 'NO', 
    CONSTRAINT employees_exceed_avgsal_ck CHECK (exceed_avgsal IN ('YES', 'NO'))); 

SQL Fiddle demo。

Answer 2

你忘了分號：

EXECUTE check_avgsal; 

但是你可以做一個簡單的UPDATE：

UPDATE employees e 
    SET avgsal_exceeded = (
WITH avg_salaries AS 
    (SELECT (max_salary + min_salary)/2 AS avg_sal, job_id FROM jobs) 
SELECT CASE 
    WHEN employee_id >= avg_sal THEN 'YES' 
    ELSE 'NO' 
    END 
FROM avg_salaries 
    WHERE a.job_id = e.job_id);