REGEXP_LIKE ASC號

Question

我有字符串「KK12340000」，我想驗證它只有KK後第4位數字按升序排列，所以我使用類似：

select case when REGEXP_LIKE('KK12340000', '^KK(?=\d{4})(?:(.)\\1*|0?1?2?3?4?5?6?7?8?9?)\d{4}$') then 1 else 0 end as valid from dual; 

但它返回0。因此，它是甚至可能在oracle中以升序來驗證數字？

Answer 1

試試這個：

SELECT CASE 
      WHEN REGEXP_LIKE (
        'KK12230000', 
        '^KK(?:(.)\\1*|0?1?2?3?4?5?6?7?8?9?)\d{4}$') 
      THEN 
      1 
      ELSE 
      0 
     END 
      AS valid 
    FROM DUAL; 

Answer 2

你也可以嘗試這樣的事情

SELECT 'KK12340000' LIKE 'KK%' AND 
SUBSTRING('KK12340000', 3, 1) - SUBSTRING('KK12340000', 4, 1) < 0 AND 
SUBSTRING('KK12340000', 4, 1) - SUBSTRING('KK12340000', 5, 1) < 0 AND 
SUBSTRING('KK12340000', 5, 1) - SUBSTRING('KK12340000', 6, 1) < 0