將指向C數組的指針傳遞給函數

Question

我對傳遞指向char數組的指針有什麼誤解？

 
Request pointer in fun: 0x7fffde9aec80 
Response pointer in fun: 0x7fffde9aec80 
Response pointer: (nil), expected: 0x7fffde9aec80 
Response itself: (null), expected: Yadda 

#include <stdlib.h> 
#include <stdio.h> 
#include <string.h> 

int get_response(char *request, char **response) { 
    response = &request; 
    printf("Request pointer in fun: %p\n", request); 
    printf("Response pointer in fun: %p\n", *response); 
    return 0; 
} 

int main() { 
    char *response = NULL, request[] = "Yadda"; 

    get_response(request, &response); 

    printf("Response pointer: %p, expected: %p\n", response, request); 
    printf("Response itself: %s, expected: %s\n", response, request); 

    return 0; 
} 

Answer 1

在功能get_response你的request地址存儲在臨時變量response。你想把它存在哪裏response分到。

*response = request; 

Answer 2

嘗試*response = request：要響應指針的內容設置爲請求的內容。

Answer 3

你想*response = request;而不是response = &request;在get_response(...)

Answer 4

首先，與當期的聲明和您的get_response用法，參數response被聲明爲char**，這是一個指向char*，例如一個指向指針的指針。如果您不知何故需要修改實際指向包含您的response的內存的指針，這將非常有用，但在這種情況下，這不是必需的。