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public class MyBringBackSurface extends SurfaceView implements Runnable
{
SurfaceHolder ourHolder;
Thread ourThread;
boolean isRunning=false;
Bitmap[] bitmap={BitmapFactory.decodeResource(getResources(), R.drawable.dice1),
BitmapFactory.decodeResource(getResources(), R.drawable.dice2),
BitmapFactory.decodeResource(getResources(), R.drawable.dice3)
};
public MyBringBackSurface(Context context) {
super(context);
ourHolder=getHolder();
}
@Override
public void run()
{
while(isRunning)
{
if(!ourHolder.getSurface().isValid())
continue;
Canvas canvas = ourHolder.lockCanvas();
Bitmap[] bitmap={BitmapFactory.decodeResource(getResources(), R.drawable.dice1),
BitmapFactory.decodeResource(getResources(), R.drawable.dice2),
BitmapFactory.decodeResource(getResources(), R.drawable.dice3)};
for(timer=0; timer< bitmap.length; timer++)
{
canvas.drawBitmap(bitmap[timer], 10,20,null);
}
ourHolder.unlockCanvasAndPost(canvas);
}
}
public void pause() {
isRunning = false;
while(true)
{
try
{
ourThread.join();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
break;
}
ourThread=null;
}
public void resume()
{
isRunning = true;
ourThread= new Thread(this);
ourThread.start();
}
}
}
您正在以相同的座標繪製圖像。這就是爲什麼你看到最後一次繪製canvas.drawBitmap(位圖[定時器],10,20,空); – Raghunandan
請在文本正文中添加一個問題。你想要的是每個'bitmap []'條目要被順序繪製來模擬一個die roll? –
@Raghunandan:是的,我知道我正在使用同一個座標..但實際上這是我的要求。其實我有一個骰子的形象。我想像他們畫的那樣骰子在滾動。 –