如何從一個句子，通過蟒蛇提取數

Question

下面是一句「建築是100米高20米寬的」我想提取約高度爲100的號碼，所以我用

question = input " " 
height = re.findall(r'(\d+) m tall', question) 

但是，有時句子不是「100米高」，而是「100米高」。在這種情況下，我的程序不能再提取我想要的號碼了。有沒有辦法改善我的課程，讓它工作，而不管句子包含「高」還是「高」。

Answer 1

您可以通過|檢查「高或高」條件：

(\d+) m (tall|high) 

演示：

>>> re.findall(r'(\d+) m (tall|high)', 'a building is 100 m tall and 20 m wide') 
[('100', 'tall')] 
>>> re.findall(r'(\d+) m (tall|high)', 'a building is 100 m high and 20 m wide') 
[('100', 'high')] 

如果你想要不被捕獲的話，使用非捕獲組：

(\d+) m (?:tall|high) 

Answer 2

>>> import re 
>>> re.findall(r'(\d+) m (?:tall|high)', "a building is 100 m tall and 20 m wide") 
['100'] 
>>> re.findall(r'(\d+) m (?:tall|high)', "a building is 100 m high and 20 m wide") 
['100'] 

Answer 3

根據您的要求，正則表達式應該匹配任何術語「高」或「高」。

  i.e., ?:tall|high 
     where, ?: means 'matches any of' 
       and,  | means 'or' 

因此，解決方案可以像：

>>> re.findall(r'(\d+) m (?:tall|high)', question) 


['100']