如何提取蟒蛇快譯通的值的每一個可能值列出

Question

DICTA={'bw':['BW','VW'],'b':['BB','VV'],'a':['AA']} 
DICTB={'yn':['$YN','$YNN'],'ye':['$YE','A$Y'],'y':['Y$']} 

如何到2快譯通的每一個可能的值提取到

["BWYN","VWYN","BBYN","VVYN","AAYN","BWYNN","VWYNN","BBYNN","VVYNN","AAYNN", 
"BWYE","VWYE","BBYE","VVYE","AAYE","ABWY","AVWY","ABBY","AVVY","AAAY", 
"YBW","YVW","YBB","YVV","YAA"] 

PS：順序並不重要

PPS：不做作業，但想知道如何以有效的方式實施。以下基本主題

Answer 1

許多可能的輕微變種：

print [y.replace('$', x) 
    for y in (v for y in DICTB.values() for v in y) 
    for x in (v for y in DICTA.values() for v in y) 
] 

Answer 2

我喜歡去與itertools自己，但本質上是相同Alex的解決方案：

from itertools import product 

[ 
    y.replace('$', x) 
    for (x, y) in product(sum(DICTA.values(), []), sum(DICTB.values(), [])) 
]