查詢不等於多個值

Question

我有編碼該位，可能有人請幫助我，使查詢正確的，我想我有，但我剛剛收到查詢錯誤
原始代碼：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 $myf ORDER BY level DESC,userid ASC LIMIT 20"); 

我的失敗編輯代碼：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20"); 

Answer 1

使用此

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20"); 

ÿ OU不能放兩個where子句

FYI：http://dev.mysql.com/doc/refman/5.0/en//select.html

Answer 2

代替

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20"); 

你應該，（刪除第2位置）

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");