如何找到部分字符串並將其回顯出來？

Question

$string = "David Smith (Local/202@from-queue/n from SIP/202) (ringinuse enabled) (Not in use) has taken 1 calls (last was 843 secs ago)";

我需要呼出(1)的呼叫。

我曾嘗試：

$taken_calls = substr($string, 'taken ', 4); 

我該怎麼辦呢？謝謝。

Answer 1

$string = "David Smith (Local/202@from-queue/n from SIP/202) (ringinuse enabled) (Not in use) has taken 1 calls (last was 843 secs ago)"; 
$result= array(); 
preg_match("/taken\s(\d+)/", $string, $result); 

var_dump($result); 

結果：

array(2) { 
      [0]=> string(7) "taken 1" 
      [1]=> string(1) "1" // this is your number 
} 

編輯：現在，這個數字可能會超過1個位數

Answer 2

使用正則表達式：

<?php 
$string = "David Smith (Local/202@from-queue/n from SIP/202) (ringinuse enabled) (Not in use) has taken 1 calls (last was 843 secs ago)"; 
$matches = array(); 

if (1 === preg_match('/taken (\d+) calls/', $string, $matches)) { 
    echo $matches[1]; 
}