我應該如何循環這個程序？

Question

基本上我需要循環這個。我創建了一個遊戲，您可以在runescape中回答關於魚的問題，並且我希望它能像說'再去一次'那樣循環。我會怎麼做呢？

import java.util.Scanner; 
public class GameDriver 
{ 
    public static void main(String a[]) 
{ 
    Game g = new Game(); 
    Scanner s = new Scanner(System.in); 
    String buf = null; 

    for(int i = 0; i < 4; i++) 
    { 
    System.out.print(g.askQuestion()); 
    buf = s.nextLine(); 

    if(g.confirm(buf)) 
     System.out.println("You're Right!"); 
    else 
     System.out.println("You're Wrong..."); 
    } 

    System.out.println("You got a " + g.getScore()); 
    } 
} 

Answer 1

PFB完整的代碼爲「你又來了」計劃：

import java.util.Scanner; 

public class GameDriver { 

    public static void Gamer(Scanner s) { 

     Game g = new Game(); 

     String buf = null; 

     for (int i = 0; i < 4; i++) { 
      System.out.print(g.askQuestion()); 
      buf = s.nextLine(); 

      if (g.confirm(buf)) 
       System.out.println("You're Right!"); 
      else 
       System.out.println("You're Wrong..."); 
     } 

     System.out.println("You got a " + g.getScore()); 

    } 

    public static void main(String a[]) { 

     Scanner s = new Scanner(System.in); 

     try { 

      while (true) { 
       System.out.print("Press Enter to continue; Type Exit to quit"); 

       if (s.nextLine().equalsIgnoreCase("exit")) { 
        s.close(); 
        break; 
       } 

       Gamer(s); 
      } 

     } catch (Exception e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } 

    } 
} 

Answer 2

你可以做，而（真）循環，然後如果用戶輸入退出剛剛突破，像這樣的循環：

if (buf.equals("quit")) 
    break; 

Answer 3

按我理解你的問題，你要循環的對如果我錯了，請仔細糾正我。

char c='y';//'y' means user wants to go again 
while(c=='y')// to check the user reply. 
{ 

    for(int i = 0; i < 4; i++) 
    { 
     System.out.print(g.askQuestion()); 
     buf = s.nextLine(); 

     if(g.confirm(buf)) 
      System.out.println("You're Right!"); 
     else 
      System.out.println("You're Wrong..."); 
     } 

     System.out.println("You got a " + g.getScore()); 
     System.out.println("Do you wanna go again?"); 
     c=s.next.charAt(0); 
} 

Answer 4

這是最短的解決方案讓您的所有代碼邏輯是：

import java.util.Scanner; 

public class GameDriver { 

    public static void Gamer(Scanner s) { 

     Game g = new Game(); 

     String buf = null; 

     for (int i = 0; i < 4; i++) { 
      System.out.print(g.askQuestion()); 
      buf = s.nextLine(); 

      if (g.confirm(buf)) 
       System.out.println("You're Right!"); 
      else 
       System.out.println("You're Wrong..."); 
     } 

     System.out.println("You got a " + g.getScore()); 

     System.out.print("Press Enter to continue; Type Exit to quit"); 

     if (s.nextLine().equalsIgnoreCase("exit")) { 
      s.close(); 
      System.exit(0); 
     } 

     Gamer(s); 
    } 

    public static void main(String a[]) { 
     Gamer(new Scanner(System.in)); 
    } 
}