獲取表列的速度比信息架構更快？

Question

我用下面從表中獲取的列名：

SELECT 
    COLUMN_NAME 
FROM 
    INFORMATION_SCHEMA.COLUMNS 
WHERE 
    TABLE_NAME = mytable 

但它需要一個很長的時間來作出迴應。有更快的選擇嗎？

Answer 1

你可以定義模式，只選擇需要的列：

SELECT table_schema, 
     table_name, 
     column_name, 
     data_type, 
     character_maximum_length, 
     is_nullable, 
     column_default, 
     numeric_precision, 
     numeric_scale 
    FROM information_schema.columns 
    WHERE table_name = 'yourtable' 
    AND table_schema = 'yourschema' 
ORDER BY table_schema, 
     table_name, 
     ordinal_position 

Answer 2

我有一個MySQL + PHP的解決方案去

$query = 'EXPLAIN ' . $this->tableName; 
     $statement = $this->db->prepare($query); 
     $statement->execute(); 

     while ($row = $statement->fetch()) { 
      $this->dbColumns[] = $row['Field']; 
     } 

似乎是相當快速