按年，月，日分隔

Question

如何分隔年，月，日在日期。並且每個都放在變量中？

1390/02/05 
$year = '1390'; 
$month = '02'; 
$day = '05'; 

對於

Answer 1

喜歡的東西：

list($year, $month, $day) = explode('/', '1390/02/05', 3); 

Answer 2

你可以這樣做：

$date = '1390/02/05'; 
$array = $explode('/', $date); 

$year = $array[0]; 
$month = $array[1]; 
$day = $array[2]; 

Answer 3

list($year, $month, $day) = explode('/', '1390/02/09', 3); 

Answer 4

$timestamp = strtotime('1390/02/05'); 
$year = date('Y', $timestamp); 
$month = date('m', $timestamp); 
$day = date('d', $timestamp);