我目前正在嘗試製作一個跟隨鼠標的彩虹線索。我用Linkedlist來繪製我鼠標的點,所以跟蹤一直跟蹤。線索本身看起來很完美,它只有線索中看起來不正確的顏色。我想讓他們淡入對方。有人告訴我使用線性插值,並且在查看一段時間之後,它似乎會起作用,我只是不知道如何實現它。如何使用線性插值和鏈接列表製作顏色漸變?
這是我的代碼至今:
import impsoft.bots.ColorBot;
import impsoft.scripting.ibot.interfaces.AutoPaint;
import impsoft.scripting.types.ColorScript;
import java.awt.BasicStroke;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.RenderingHints;
import java.util.Deque;
import java.util.LinkedList;
import impsoft.scripting.ibot.structs.XY;
import impsoft.scripting.types.ColorSkeltonScriptable;
import impsoft.scripting.types.parallel.scriptjobs.ScriptJob;
public class MouseTrail extends ColorScript implements AutoPaint {
public MouseTrail(ColorBot c) {
super(c);
}
public void script() throws InterruptedException {
while(true) {
mt.setSize(500);
mt.exec();
sleep(100);
}
}
public static String name = "Mouse trail test";
public static String author = "Llaver";
public static String description = "test for mouse trail";
public static double version = 1.00;
public class MouseTrail2 extends ScriptJob implements AutoPaint {
private int size;
private final ColorSkeltonScriptable cs;
private final Deque<XY> trail = new LinkedList<XY>();
private final Color[] rainbow = new Color[]{
Color.RED, Color.YELLOW, Color.GREEN, Color.CYAN, Color.BLUE, Color.magenta
};
public MouseTrail2(ColorSkeltonScriptable cs) {
super(cs);
this.cs = cs;
}
public void setSize(int s) {
size = s;
s = 200;
}
public void runV() {
try {
while (true) {
synchronized (trail) {
if (trail.size() >= size) {
trail.pop();
}
trail.offer(cs.getCurrentMouseXY());
}
sleep(1);
}
} catch (InterruptedException e) {
}
}
@Override
public void paint(Graphics g) {
final Graphics2D g2d = (Graphics2D) g;
g2d.setStroke(new BasicStroke(3, BasicStroke.CAP_BUTT, BasicStroke.JOIN_ROUND));
g2d.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
synchronized (trail) {
float perc;
int idx;
for(int i = 1 ; i < trail.size() - 1 ; i++){
XY current = ((LinkedList<XY>) trail).get(i);
XY next = ((LinkedList<XY>) trail).get(i - 1);
perc = ((float)i/trail.size()) * 100f;
idx = Math.round((perc * (float)rainbow.length)/100f);
if(idx >= rainbow.length)idx -= 1;
g2d.setColor(rainbow[idx]);
g.drawLine(current.x, current.y, next.x, next.y);
}
}
}
}
@Override
public void paint(Graphics arg0) {
}
private MouseTrail2 mt = new MouseTrail2(this);
}
一些圖片:
這就是我現在所擁有的:
http://img11.imageshack.us/img11/3031/mousetrailhavenow.png
這是林試圖獲得:
http://img594.imageshack.us/img594/7381/mousetrailtryingtoget.png
這是否可能使這個更清楚一點?
當我嘗試路徑的顏色取決於它在屏幕上的位置而不是它在後面的路徑中的位置。我需要它,所以它可以從LinkedList中獲取點數並將其顏色基於此..如果這很有意義 –
任何你可以使用[這裏](http://stackoverflow.com/questions/6992633/painting-the-slider-圖標的-JSlider的/ 6996263#6996263)? – trashgod
沒有多少= /我已經嘗試lineargradientpaint,但它不工作,我也需要它。它使一個盒子,而不是遵循指定的點 –