SQLite 3 - 如何從下面的代碼中選擇MIN（）中的下一個值..以及如何自動執行下一個，下一個...值

Question

   MIN(CASE 
        WHEN Type = 435 THEN TimeStamp 
       END) AS InTime,     
       MIN(CASE 
        WHEN Type = 324 THEN TimeStamp 
       END) AS OutTime 

上面的代碼使用min（）來查找最小值，如何找到下一個最小值以及如何獲得所有下一個....值...

Answer 1

SELECT TimeStamp AS InTime 
FROM MyTable 
WHERE Type = 435 
ORDER BY Timestamp; 

SELECT TimeStamp AS OutTime 
FROM MyTable 
WHERE Type = 324 
ORDER BY Timestamp;