使用組和多個表的MySQL查詢的級聯結果

我有5個表（括號鍵）：

trips (tripId) 
trips_moments (tripId, momentId) 
moments (momentId) 
moments_images (momentIs, imageId) 
images (imageId)

在我的情況我有1班，其中包含2個瞬間，每一刻都包含5張圖片。

我想結果在現場得到「瞬間」：代替

166;Kościuszko mound in Cracow;2012-11-08 15:38:14;6;F50MTTZK;jpg;6R2XJB9X| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;19;66B7VQ84;jpg;ILQYDQUC

：

166;Kościuszko mound in Cracow;2012-11-08 15:38:14;6;F50MTTZK;jpg;6R2XJB9X| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;7;9PY1BZD1;jpg;TP7U07ST| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;8;VPGPFMMS;jpg;VF95BNNQ| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;9;EC7NL3HC;jpg;PD1CEQE6| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;10;8J1OT7IT;jpg;ZL8WAWCJ| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;19;66B7VQ84;jpg;ILQYDQUC| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;20;HZIPGJY7;jpg;FOOWJ8BV| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;21;9JOXXPJQ;jpg;ZIVJ5V7K| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;22;IS1JPW1N;jpg;31M4XVBM| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;23;OTOWNDZA;jpg;C03UFMBK

你可以在我的結果，與166和167記錄重複看許多時候包含瞬間的圖像。

我當前的查詢：

SELECT 
`t`.`tripId`, 
`t`.`title`, 
`t`.`when`, 
GROUP_CONCAT(
    DISTINCT(
    CONCAT(
     m.momentId, ';', m.title, ';', m.created, ';', i.imageId, ';', i.fileNameBase, ';', i.fileNameExtension, ';', i.directory) 
    ) 
    SEPARATOR '|' 
) AS `moments` 
FROM `trips` AS `t` 
LEFT JOIN `trips_moments` AS `tm` ON t.tripId = tm.tripId 
LEFT JOIN `moments` AS `m` ON tm.momentId = m.momentId 
LEFT JOIN `moments_images` AS `mi` ON m.momentId = mi.momentId 
LEFT JOIN `images` AS `i` ON mi.imageId = i.imageId 
WHERE (t.userId = '1') 
GROUP BY `t`.`tripId` 
ORDER BY `t`.`tripId` ASC

當前表結構：

CREATE TABLE IF NOT EXISTS `images` (
    `imageId` int(11) NOT NULL AUTO_INCREMENT, 
    `userId` int(11) NOT NULL, 
    `title` varchar(128) NOT NULL, 
    `description` text NOT NULL, 
    `fileNameBase` varchar(64) NOT NULL, 
    `fileNameExtension` varchar(4) NOT NULL, 
    `directory` varchar(64) NOT NULL, 
    `source` varchar(32) NOT NULL, 
    `created` datetime NOT NULL, 
    PRIMARY KEY (`imageId`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ; 

CREATE TABLE IF NOT EXISTS `moments` (
    `momentId` int(11) NOT NULL AUTO_INCREMENT, 
    `title` varchar(128) NOT NULL, 
    `userId` int(11) NOT NULL, 
    `created` datetime NOT NULL, 
    PRIMARY KEY (`momentId`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ; 

CREATE TABLE IF NOT EXISTS `moments_images` (
    `momentId` int(11) NOT NULL, 
    `imageId` int(11) NOT NULL, 
    PRIMARY KEY (`momentId`,`imageId`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

CREATE TABLE IF NOT EXISTS `trips` (
    `tripId` int(11) NOT NULL AUTO_INCREMENT, 
    `userId` int(11) NOT NULL, 
    `title` varchar(128) NOT NULL, 
    `when` date NOT NULL, 
    `created` datetime NOT NULL, 
    PRIMARY KEY (`tripId`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ; 

CREATE TABLE IF NOT EXISTS `trips_moments` (
    `tripId` int(11) NOT NULL, 
    `momentId` int(11) NOT NULL, 
    PRIMARY KEY (`tripId`,`momentId`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

來源

2012-11-08 sanneo

購買你有多個圖像的每個時刻？你無法獲得預期的輸出。這三個文件名都不是附在166：F50MTTZK，VPGPFMMS，8J1OT7IT上。 –

結果是正確的，每個時刻有5個圖像。如果你只想選擇一張圖片，mysql應該在哪些條件下選擇一張圖片？最新的？最老的？隨機？ – Kaii

@Kaii，我想從rowset中得到第一張圖片，如果有可能按名稱或日期排列，那麼這將是完美的 – sanneo

我現在不能測試，但是這可以給你一個想法，我改變moemnt_images參加這樣的：

LEFT JOIN `moments_images` AS `mi` ON m.momentId = mi.momentId 
AND imageId = (select min(imageId) from moments_images where momentId=m.momentId)

完整查詢：

SELECT 
`t`.`tripId`, 
`t`.`title`, 
`t`.`when`, 
GROUP_CONCAT(
    DISTINCT(
    CONCAT(
     m.momentId, ';', m.title, ';', m.created, ';', i.imageId, ';', i.fileNameBase, ';', i.fileNameExtension, ';', i.directory) 
    ) 
    SEPARATOR '|' 
) AS `moments` 
FROM `trips` AS `t` 
LEFT JOIN `trips_moments` AS `tm` ON t.tripId = tm.tripId 
LEFT JOIN `moments` AS `m` ON tm.momentId = m.momentId 
LEFT JOIN `moments_images` AS `mi` ON m.momentId = mi.momentId and imageId = (select min(imageId) from moments_images where momentId=m.momentId) 
LEFT JOIN `images` AS `i` ON mi.imageId = i.imageId 
WHERE (t.userId = '1') 
GROUP BY `t`.`tripId` 
ORDER BY `t`.`tripId` ASC

來源

2012-11-08 23:29:41

它正在工作，謝謝。我認爲需要做子查詢，但希望有沒有子查詢的另一種解決方案。謝謝你們的快速解答。 – sanneo

@Kaii

我兩列用這個分組，但由於預期的結果並不：

在結果我得到兩個記錄在這些領域的價值「瞬間」：

月1日的記錄）

166;Kościuszko mound in Cracow;2012-11-08 15:38:14;9;EC7NL3HC;jpg;PD1CEQE6| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;6;F50MTTZK;jpg;6R2XJB9X| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;8;VPGPFMMS;jpg;VF95BNNQ| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;10;8J1OT7IT;jpg;ZL8WAWCJ| 
166;Kościuszko mound in Cracow;2012-11-08 15:38:14;7;9PY1BZD1;jpg;TP7U07ST

第二記錄）

167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;20;HZIPGJY7;jpg;FOOWJ8BV| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;22;IS1JPW1N;jpg;31M4XVBM| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;19;66B7VQ84;jpg;ILQYDQUC| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;21;9JOXXPJQ;jpg;ZIVJ5V7K| 
167;Pope John Paul II (Jan Paweł 2) home town - Wadowice;2012-11-08 15:57:15;23;OTOWNDZA;jpg;C03UFMBK

我想在我的問題中得到一個結果，當然如果可能的話。

來源

2012-11-08 23:34:03 sanneo

使用組和多個表的MySQL查詢的級聯結果

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