3
解析字符串到JSONObject的我有以下代碼:爪哇 - 使用GSON
JsonParser parser = new JsonParser();
System.out.println("gson.toJson: " + gson.toJson(roomList));
JsonObject json2 = parser.parse("{\"b\":\"c\"}").getAsJsonObject();
System.out.println("json2: " + json2);
JsonObject json = parser.parse(gson.toJson(roomList)).getAsJsonObject();
System.out.println("json: " + json);
,它給了我下面的輸出:
gson.toJson: [{"id":"8a3d16bb328c9ba201328c9ba5db0000","roomID":9411,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328b9f3a01328b9f3bb80000","roomID":1309,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328ba09101328ba09edd0000","roomID":1304,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bb8af640000","roomID":4383,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd271fe0001","roomID":5000,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd2e0e30002","roomID":2485,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd3087b0003","roomID":6175,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd35a840004","roomID":3750,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd366250005","roomID":370,"numberOfUsers":4,"roomType":"BigTwo"},{"id":"402881e4328bb83601328bd3807d0006","roomID":9477,"numberOfUsers":4,"roomType":"BigTwo"}]
json2: {"b":"c"}
java.lang.IllegalStateException: This is not a JSON Object.
有人可以請幫我分析我的JSON字符串到的JSONObject ?我已經在http://jsonlint.com/中檢查過我的json是有效的。非常感謝:)
編輯:
我終於有answer..it的,因爲由於JSON結構.. 我已經把它變成一個JSONObject第一,像這樣
JsonObject jsonObj = new JsonObject();
jsonObj.addProperty(ServerConstants.JSONoutput, gson.toJson(roomList));
然後我會反序列化像
List<RoomData> roomList = gson.fromJson(jsonObj.get(CardGameConstants.JSONoutput).toString(), listType);
for (RoomData roomData : roomList) {
System.out.println(roomData.getRoomID());
}
你似乎使用json-simple而不是gson,JSONArray上的String構造函數在gson中無效 – teejay