比較兩個數組中的元素，在同類指標相互

我有兩個數組有相同數目的成員（總是）的$userInputArr=array("z","z","E","z","z","E","E","E","E","E");和$user2InputArr=array("a","a","a","z","a","E","E","E","a","E");我知道如何找到匹配成員在兩個數組。這裏我想找到具有相似索引的匹配元素，例如如果$ userInputArr [4] == $ user2InputArr [4]，則增加$匹配。在我下面的嘗試中，我通過兩個數組循環，但我無法獲得$匹配增量。比較兩個數組中的元素，在同類指標相互

$match = 0; 
for ($c =0; $c < count($$userInputArr); $c++) { 
    for ($d = $c; $d<count($user2InputArr);$d++) { 
     if ($userAnsStrArr[$c] == $userInputArr[$d]) { 
      $match = $match +1; 
     } 
    } 
}

來源

2017-08-14 jimiss

「foreach」會不會更適合？ – Script47

@ Script47我也嘗試了一個foreach循環，沒有成功 – jimiss

在這裏嵌套兩個循環是無稽之談。你想循環訪問數組中的_one_，並在訪問另一個數組時訪問對應的元素。 – CBroe

這個問題是PHP函數array_intersect_assoc()一個很好的例子：

$array1 = array("z","z","E","z","z","E","E","E","E","E"); 
$array2 = array("a","a","a","z","a","E","E","E","a","E"); 

// Find the matching pairs (key, value) in the two arrays 
$common = array_intersect_assoc($array1, $array2); 
// Print them for verification 
print_r($common); 

// Count them 
$match = count($common); 
echo($match." common items.\n");

輸出是：

Array 
(
    [3] => z 
    [5] => E 
    [6] => E 
    [7] => E 
    [9] => E 
) 
5 common items.

來源

2017-08-14 10:39:54 axiac

因此，減免在臃腫的頁面上看到明智的答案。沒有知情的PHP開發人員會做任何事情，除此之外！ – mickmackusa

$match = 0; 
for ($c =0; $c < count($$userInputArr); $c++) { 

    if ($userAnsStrArr[$c] == $userInputArr[$c]) { 
      $match = $match +1; 
     } 

}

你應該做的是這樣的。

來源

2017-08-14 10:30:37 d3no

'count（$$ userInputArr）'上有一個輸入錯誤，它阻止了它的工作。此外，我會迭代，直到兩個數組的較小長度，以避免在第二個數組比第一個數組短時觸發通知。 – axiac

這對我的作品

$i = sizeof($userInputArr); 

$match = 0; 
for($j = 0; $j < $i; $j++) 
    if ($userInputArr[$j] == $user2InputArr[$j]) { 
     $match = $match +1; 
    }

來源

2017-08-14 10:35:13

'sizeof'可能會與別的東西混淆，所以最好使用'count'。 – Script47

我將'$ i'設置爲兩個數組的較小長度，以避免在第二個數組比第一個數組短的情況下觸發通知。 – axiac

在這種情況下「我有兩個成員數相同的數組（總是）」。我簡化了它。我是新的在stackoverflow。 –

下面是代碼您。只需使用一個foreach，穿越的第一array，並且在第二array檢查爲key-value。

$s = array("z","z","E","z","z","E","E","E","E","E"); 
$b = array("a","a","a","z","a","E","E","E","a","E"); 

foreach($s as $k => $v) { 
    if($b[$k] === $s[$k]) { 
     echo $k . ' is the index where keys and values exactly match with value as ' . $b[$k]; 
    } 
}

輸出：

3 is the index where keys and values exactly match with value as z 
5 is the index where keys and values exactly match with value as E 
6 is the index where keys and values exactly match with value as E 
7 is the index where keys and values exactly match with value as E 
9 is the index where keys and values exactly match with value as E

這裏是鏈接：https://3v4l.org/eX0r4

來源

2017-08-14 10:41:04

我看來你的代碼並不需要兩個for循環增加比賽中的單圈見下面的代碼。

<?php 
$userInputArr=array("z","z","E","z","z","E","E","E","E","E"); 
$user2InputArr=array("a","a","a","z","a","E","E","E","a","E"); 
$match = 0; 
for ($c =0; $c < count($userInputArr); $c++) { 
    if ($user2InputArr[$c] == $userInputArr[$c]) { 
     $match = $match + 1; 
    } 
} 
echo $match; 
?>

來源

2017-08-14 10:49:48

比較兩個數組中的元素，在同類指標相互

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