大家好模型,我給在功能如下錯誤消息:數據
$query = $this->db->get();
$result = $query->result();
$data[] = $result;
但作爲一個PHP錯誤遇到
嚴重性我得到的錯誤:請注意
消息:未定義變量:數據
文件名:型號/ survey_model.php
行號:845
空
什麼是這一點。有人可以幫我請
function get_actual_details_model($fin_year,$state){
$this->db->select('*');
$this->db->from('survey_respondent_info');
$this->db->where('state', $state);
$queryYr = $this->db->get();
$resYr = $queryYr->result();
foreach ($resYr as $surveyId) {
$this->db->select('budgets.*, budget_funding.*, marketing_budget.*, personnel_budget.*, grants_budget.*');
$this->db->from('budgets');
$this->db->join('budget_funding', 'budget_funding.budget_id = budgets.budget_id', 'left');
$this->db->join('marketing_budget', 'marketing_budget.budget_id = budgets.budget_id', 'left');
$this->db->join('personnel_budget', 'personnel_budget.budget_id = budgets.budget_id', 'left');
$this->db->join('grants_budget', 'grants_budget.budget_id = budgets.budget_id', 'left');
$this->db->where('budgets.financial_year',$fin_year);
$this->db->where('budget_option_id', 1);
$this->db->where('survey_id', $surveyId->survey_id);
$data = array();
$query = $this->db->get();
$result = $query->result();
$data[] = $result;
}
return $data;
}
你在哪裏設置$的數據? – Anigel
[PHP:「Notice:Undefined variable」和「Notice:Undefined index」]的可能重複(http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index) –