mysql select其中count超過x

Question

如何創建一個MySQL查詢，要求同一查詢的總計數超過x？

如

$result=mysql_query("select * from DB where BANANAS='1' and ORANGES='2' and [COUNT OF THIS QUERY IS MORE THAN 5]"); 

謝謝！

中號

編輯

更清晰......，什麼林尋找的是：

$result=mysql_query("select * from DB where BANANAS='1' and ORANGES='2' group by PINEAPPLES order by SUM(SUGAR) desc limit 1 and [[[COUNT OF PINEAPLES WHERE BANANAS='1' IS MORE THAN 5]]]"); 

希望幫助...

Answer 1

and (select count(*) from foo where bar) > 5

或

group by baz having count(*) > 5

Answer 2

目前還不清楚你問什麼。但是，只有當他們是6個或更多，如果你希望所有的行（即匹配的標準），但是，這裏有一種方法：

SELECT * 
FROM tableName   -- have you really named your table "DB"? 
WHERE bananas = 1 
    AND oranges = 2 
    AND (SELECT COUNT(*) 
     FROM tableName 
     WHERE bananas = 1 
      AND oranges = 2 
    ) > 5 ; 

和另：

SELECT * 
FROM tableName   -- have you really named your table "DB"? 
WHERE bananas = 1 
    AND oranges = 2 
    AND (SELECT 1 
     FROM tableName 
     WHERE bananas = 1 
      AND oranges = 2 
     LIMIT 1 OFFSET 5 
    ) IS NOT NULL ; 

Answer 3

如果你想選擇到只有在計數超過5時纔會發生，那麼以下查詢可能會有用。

select count(*) from DB as X where BANANAS='1' and ORANGES='2'; 

select * from DB where BANANAS='1' and ORANGES='2' IF (CAST(X as UNSIGNED) > 5);