爲Oracle中的每個重複值自動遞增

Question

我正在使用Oracle數據庫集成器（ODI）爲新表創建接口。

我想要做的是逐漸增加一個數字，爲​​每個重複出現的另一列中的值。例如，對於表：

Person_ID | ... 
32   | ... 
45   | ... 
32   | ... 
67   | ... 
45   | ... 
45   | ... 

接口將在目標表輸出如下：

Person_ID | Sequence_Number | ... 
32  |  1   | ... 
45  |  1   | ... 
32  |  2   | ... 
67  |  1   | ... 
45  |  2   | ... 
45  |  3   | ... 

我試圖通過進入不同的SQL查詢到在實現文本編輯器來做到這一點映射屬性，但似乎我實際上無法使其逐漸增加。

任何幫助將不勝感激！

Answer 1

可以使用row_number()，或rank()與over(partition by personId order by personId)

select personId, 
     row_number() over(partition by personId order by personId) Sequence_Number 
from your_table 

編輯：如果要排序的正是像你提到的期望的輸出結果，你需要做的order by rownum兩次，以保證所需的排序：

select personId, 
     row_number() over(partition by personId order by rownum) Sequence_Number 
from your_table 
order by rownum 

下面是上面查詢檢查：

---

SQL> create table your_table (personId int); 

Table created. 

SQL> insert all 
    2  into your_table values(32) 
    3  into your_table values(45) 
    4  into your_table values(32) 
    5  into your_table values(67) 
    6  into your_table values(45) 
    7  into your_table values(45) 
    8  select * from dual; 

6 rows created. 

SQL> commit; 

Commit complete. 

SQL> select personId, 
    2   row_number() over(partition by personId order by rownum) Sequence_Number 
    3 from your_table; 

    PERSONID SEQUENCE_NUMBER 
---------- --------------- 
     32    1 
     32    2 
     45    1 
     45    2 
     45    3 
     67    1 

6 rows selected. 

SQL> select personId, 
    2   row_number() over(partition by personId order by rownum) Sequence_Number 
    3 from your_table 
    4 order by rownum; 

    PERSONID SEQUENCE_NUMBER 
---------- --------------- 
     32    1 
     45    1 
     32    2 
     67    1 
     45    2 
     45    3 

6 rows selected. 

SQL> drop table your_table; 

Table dropped. 

SQL>