響應我試圖讓在組合函數返回與Facebook API reqeust。得到FB API JavaScript程式
var g_ret = true;
function uploadImagesFbCounter(anz){
var gid='';
$("div[id ^= 'gallerydetail']").each(function (i) {
gid = this.id.split('-');
gid = parseInt(gid[1]);
})
if(gid==0) return true;
FB.api('/me', function(response) {
//console.log(response);
var uid = response.id;
if(!anz){
g_ret = $.ajax({
type: "POST",
async:false,
url: "api/gallerie_anz_speich.php",
data: "uid="+uid+"&op=get&gid="+gid
});
if(g_ret.response >= 20) {
g_ret = false;
}
} else {
g_ret = $.ajax({
type: "POST",
async:false,
url: "api/gallerie_anz_speich.php",
data: "uid="+uid+"&op=set&gid="+gid
});
//console.log(g_ret.response);
g_ret = '<span style="padding:0 5px;">Noch '+(20-g_ret.response)+'Fotos</span>';
console.log(g_ret);
}
});
return g_ret;
}
我做了什麼,我得到一個空的答覆....請幫助!
感謝你有很大的幫助:) – 2012-03-10 19:39:00
您還需要你的$就成功回調調用的onSuccess。我不知道jQuery,所以你必須弄清楚。 – JoJo 2012-03-10 23:30:54