所以我有3個表:1.4.3 MySQL的結果
student
-studentid
-studentname
course_offerings
-course_offeringid
-course
-type
scores
-student_studentid
-course_offering_course_offeringid
-score
當我做我的查詢:
SELECT studentid, studentname, course, type, score
FROM scores
INNER JOIN student ON scores.student_studentid = student.studentid
INNER JOIN course_offering ON scores.course_offering_course_offeringid = course_offering.course_offeringid
我得到的是這樣的輸出:
studentid studentname course type score
123345 Doe, John 123 Exam 1 100
123345 Doe, John 123 Exam 2 95
123345 Doe, John 123 Exam 3 75
123345 Doe, John 123 Final 93
543211 Doe, Jane 123 Exam 1 70
543211 Doe, Jane 123 Exam 2 91
543211 Doe, Jane 123 Exam 3 99
543211 Doe, Jane 123 Final 43
.
.
.
我會類似於輸出爲:
studentid studentname course Exam 1 Exam 2 Exam 3 Final
123345 Doe, John 123 100 95 75 93
543211 Doe, Jane 123 70 91 99 43
這只是MySQL可能嗎?
我認爲它可能..我可以問,如果這是你有完整的表結構?我認爲你在course_offering和成績表上都缺少studentid。 – mCube
我認爲在'scores'中有一個studentid,沒有理由在'offerings'表中找到它。 – kirelagin
是的,我相信這是正確的。對於那個很抱歉。我還建議您刪除「類型」字段並將其放在「分數」表上。 – mCube