如何在Codeigniter和數據庫中使用「is_unique」是一個mongodb

如何使用戶名在驗證和輸出中唯一，其格式爲「JSON」。其實我使用Codeigniter構建一個應用程序和MongoDB作爲數據庫。我不知道是否在MongoDB中工作的「is_unique」，但我嘗試過，但它不工作。如何在Codeigniter和數據庫中使用「is_unique」是一個mongodb

控制器：

公共職能create_customer（）{

$this->load->helper('form'); 
$this->load->library('form_validation'); 

if($this->input->post('username') != $original_value) { 
    $is_unique = '|is_unique[customer.username]' 
} else { 
    $is_unique = '' 
} 
// field name, error message, validation rules 
$this->form_validation->set_rules('first_name', 'Name', 'trim|required'); 
$this->form_validation->set_rules('last_name', 'Last Name', 'trim|required'); 
$this->form_validation->set_rules('email_address', 'Email Address', 'trim|required|valid_email'); 
$this->form_validation->set_rules('username', 'Username', 'trim|required|min_length[4]|xss_clean'.$is_unique); 
$this->form_validation->set_rules('password', 'Password', 'trim|required|min_length[4]|max_length[32]'); 
$this->form_validation->set_rules('phone_number', 'Phonenumber', 'trim|required|numeric|min_length[10]|max_length[10]'); 
$this->form_validation->set_rules('password2', 'Password Confirmation', 'trim|required|matches[password]'); 
    if($this->form_validation->run() == FALSE) 
{ 
    header('Content-Type: application/json'); 
    echo json_encode(array('success' => 'FALSE')); 
} 
else 
{ 
    $this->load->model('general/customer'); 
    $new_customer[CUSTOMER_FIRST_NAME]=$this->input->post('first_name'); 
    $new_customer[CUSTOMER_LAST_NAME]=$this->input->post('last_name'); 
    $new_customer[CUSTOMER_EMAIL]=$this->input->post('email_address'); 
    $new_customer[CUSTOMER_USERNAME]=$this->input->post('username'); 
    $new_customer[CUSTOMER_PHONE]=$this->input->post('phone_number'); 
    $new_customer[CUSTOMER_PASSWORD]=$this->input->post('password'); 
    $this->customer->is_unique(); 
    $query = $this->customer->add($new_customer); 
    header('Content-Type: application/json'); 
    echo json_encode(array('success' => 'TRUE')); 
} 
}

型號：

public function is_unique() 
{ 
    $query = $this->mongo_db->select('username'); 
    $result = mongo_db($query); 
    $count = mongo_db_num_rows($result); 
    if ($count>0) { 
    echo 'Sorry! This Username already exists!'; 
    } 
    else 
    { 

    $insert = $this->mongo_db->insert(CUSTOMER, $new_customer); 
    return $insert; 
    }

}

這是我的代碼。我想在應用程序中保持用戶名的唯一性。請幫我完成申請。

來源

2014-09-10 Ganesh UG

什麼是不工作？你的結果是什麼？您不需要編寫is_unique函數，它內置於CodeIgniter的Form_validation庫中。 – twistedpixel 2014-09-11 02:34:16

其實一個客戶必須有一個用戶名，並且它不應該與其他客戶相同。如果任何客戶在我的應用程序中輸入了一些用戶名，它應該通過拋出錯誤或消息，如「用戶名已存在」。但現在我在我的應用程序中做了一些修改，現在它工作正常。這是我修改後的代碼。 – 2014-09-17 05:59:21

控制器：

公共職能create_customer（）

{ 
    $this->load->library('form_validation'); 
    $this->form_validation->set_rules('first_name', 'Name', 'trim|required'); 
    $this->form_validation->set_rules('last_name', 'Last Name', 'trim|required'); 
    $this->form_validation->set_rules('email_address', 'Email Address', 'trim|required|valid_email'); 
    $this->form_validation->set_rules('username', 'Username', 'trim|required|min_length[4]'); 
    $this->form_validation->set_rules('password', 'Password', 'trim|required|min_length[4]|max_length[32]'); 
    $this->form_validation->set_rules('phone_number', 'Phonenumber', 'trim|required|numeric|min_length[10]|max_length[10]'); 
    $this->form_validation->set_rules('password2', 'Password Confirmation', 'trim|required|matches[password]'); 
    if($this->form_validation->run() == FALSE) 
    { 
     header('Content-Type: application/json'); 
     echo json_encode(array('success' => 'FALSE')); 
    } 
    else 
    { 
     $this->load->model('general/customer'); 
     $new_customer[CUSTOMER_FIRST_NAME]=$this->input->post('first_name'); 
     $new_customer[CUSTOMER_LAST_NAME]=$this->input->post('last_name'); 
     $new_customer[CUSTOMER_EMAIL]=$this->input->post('email_address'); 
     $new_customer[CUSTOMER_USERNAME]=$this->input->post('username'); 
     $new_customer[CUSTOMER_PHONE]=$this->input->post('phone_number'); 
     $new_customer[CUSTOMER_PASSWORD]=$this->input->post('password'); 
     if($this->customer->is_unique($new_customer[CUSTOMER_USERNAME])) 
     { 
      $query = $this->customer->add($new_customer); 
      header('Content-Type: application/json'); 
      echo json_encode(array('success' => 'TRUE')); 
     } 
     else 
     { 
      header('Content-Type: application/json'); 
      echo json_encode(array('success' => 'FALSE')); 
     } 
    } 
}

型號：

function is_unique($username) 

{ 
    $this->mongo_db->where(CUSTOMER_USERNAME, $username); 
    $query = $this->mongo_db->get(CUSTOMER); 
    return (count($query) == 0 ? true : false); 
}

來源

2014-09-17 06:04:39

模型上面的代碼由Ganesh神UG並不完全爲我工作。

更改return語句：

return (count((array)$query) == 0 ? true : false);

來源

2018-01-16 08:29:03

如何在Codeigniter和數據庫中使用「is_unique」是一個mongodb

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