如何使數組格式的變量變成數組

Question

這可能是一個簡單的問題，但是如何將如下所示的變量放入數組中。

$hot = "It","is","hot","outside"; 

執行下列操作不起作用：

$newhot = array($hot); 

我實際調用看起來的API，如：

[["P0010001","NAME","state","zip code tabulation area"], 
    ["68191","ZCTA5 99301","53","99301"]] 

我需要的是在第二線的人口（第一引號）。

執行以下操作，給了我 「68191」， 「ZCTA5 99301」， 「53」， 「99301」

$splitContent = implode("\n",array_slice(explode("\n",$populate),1,2)); 
    $newContent = str_replace(']','',$splitContent); 
    $newContent = str_replace('[','',$newContent); 

Answer 1

這

$hot = "It","is","hot","outside"; 

將在PHP中生成錯誤。但是，假設你有以下從API檢索：

$str='[["P0010001","NAME","state","zip code tabulation area"],["68191","ZCTA5 99301","53","99301"]]'; 

那麼，如果你跑這條線：

$myArray = json_decode($str); 

然後

echo "<pre>"; 
print_r($myArray); 
echo"</pre>"; 

你可以有這樣的結果：

Array 
(
    [0] => Array 
     (
      [0] => P0010001 
      [1] => NAME 
      [2] => state 
      [3] => zip code tabulation area 
     ) 

    [1] => Array 
     (
      [0] => 68191 
      [1] => ZCTA5 99301 
      [2] => 53 
      [3] => 99301 
     ) 

) 

第二行數據將被存儲在

$myArray[1] 

Answer 2

定義的數組是一樣的東西......

$hot = array("It","is","hot","outside"); 

回覆：你的API調用...

$ApiResponse = '[["P0010001","NAME","state","zip code tabulation area"],["68191","ZCTA5 99301","53","99301"]]'; 

$Response = json_decode($ApiResponse); 
$Data = $Response[1]; 

具體來說，該API將返回一個列表的列表。我們正在採用第二個（0索引）列表。 $Data現在是一樣的，如果你宣佈...

$Data = array("68191","ZCTA5 99301","53","99301"); 

編輯：測試的代碼...

$Key = '[Your Key]'; 
$ApiResponse = file_get_contents("http://api.census.gov/data/2010/sf1?key={$Key}&get=P0010001,NAME&for=zip+code+tabulation+area:99301&in=state:53"); 

print "Raw: " . print_r($ApiResponse, true) . "<hr/>"; 

$Response = json_decode($ApiResponse); 
$Data = $Response[1]; 
print "Extracted Data: " . print_r($Data, true) . "<br/>"; 

print "First bit of data: {$Data[0]}.<br/>"; 
print "Second bit of data: {$Data[1]}.<br/>";