您是否需要顯示各個費用行以及所有總計?如果沒有,你可以組由supplierinv列,總結的數額:
select supplierinv, sum(amount) as invoice_amount
from expenses group by supplierinv
,那麼你可以簡單地添加所有INVOICE_AMOUNT值的客戶端來獲取總計。
,如果你確實需要每個費用行,你可以做發票聚合客戶端相當容易:
$invtotals = array();
$grand_total = 0;
foreach (getexpenses() as $row) {
$supplierinv = $row['supplierinv'];
if (!array_key_exists($supplierinv, $invtotals)) {
$invtotals[$supplierinv] = 0;
}
$invtotals[$supplierinv] += $row['amount'];
$grand_total += $row['amount'];
}
另一種方法,如果你想顯示錶分成發票,是隻保證
$grand_total = 0;
$invoice_total = 0;
$current_invoice = -1;
foreach (getexpenses() as $row) {
if ($current_invoice > 0 && $current_invoice != $row['supplierinv']) {
show_invoice_total($current_invoice, $invoice_total);
$grand_total += $invoice_amount;
$current_invoice = $row['supplierinv'];
$invoice_total = 0;
}
$invoice_total += $row['amount'];
show_expense($row);
}
if ($current_invoice > 0) {
show_invoice_total($current_invoice, $invoice_total);
$grand_total += $invoice_amount;
}
show_grand_total($grand_total);
您可以讓數據庫做聚合每個發票和總計像這樣:
select date, supplierinv, amount,
sum(amount) over(partition by supplierinv) as invoice_amount,
sum(amount) over()
from expenses
結果由supplierinv然後命令
雖然你仍然需要做一些後處理來顯示這個明智的,所以這並沒有真正獲得任何imho。