顯示後一個的表中的所有行加入

Question

我想從表B從匹配柱接合元件

表A

+-----------+----------+------------+ 
| FirstName | LastName | Date | 
+-----------+----------+------------+ 
| Tia  | Carrera | 1975-09-18 | 
| Nikki  | Taylor | 1972-03-04 | 
| Yamila | Diaz  | 1970-03-05 | 
+-----------+----------+------------+ 

表B

+-----------+------------+ 
| code | Date  | 
+-----------+------------+ 
| 1234  | 1975-09-18 | 
| 56789  | 1972-03-04 | 
| 54856  | 1968-07-14 | 
+-----------+------------+ 

後顯示錶A中的所有行

一切我在網上找到的樣子

+-----------+----------+------------+-----------+ 
| FirstName | LastName | Date | code | 
+-----------+----------+------------+-----------+ 
| Tia  | Carrera | 1975-09-18 | 1234  | 
| Nikki  | Taylor | 1972-03-04 | 56789  | 
+-----------+----------+------------+-----------+ 

但這是結果，我想

+-----------+----------+------------+-----------+ 
| FirstName | LastName | Date | code | 
+-----------+----------+------------+-----------+ 
| Tia  | Carrera | 1975-09-18 | 1234  | 
| Nikki  | Taylor | 1972-03-04 | 56789  | 
| Yamila | Diaz  | 1970-03-05 |   | 
+-----------+----------+------------+-----------+ 

Answer 1

你想要一個left join：

select a.*, b.code 
from a left join 
    b 
    on a.date = b.date;