PostgreSQL的語法錯誤達到或接近「其中」

Question

我收到錯誤

語法錯誤達到或接近「其中」 5號線：其中拉鍊在（選擇拉鍊郵政編碼 其中城市=「薩克拉

，當我嘗試運行這段代碼。

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento'); 

是否有人看到任何容易修復錯誤？還是我拿出一些垃圾代碼？

Answer 1

只是其中條款

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) END 
where zip in (select zipcode from zips where city = 'Sacramento'); 

---

按@ a_horse_with_no_name的評論之前添加結束關鍵字

update listings 
set price = (price * (((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento') and listings.price IS NOT NULL 

Answer 2

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento') 

刪除;請再試一次

Answer 3

SQL CASE expression需要以END關鍵字結尾。