SQL：使用with-clause in「not in」-operator

Question

是否可以實現類似這樣的事情？

WITH subQ(attr1) as (SELECT attr1 FROM tab1) 

SELECT tab2.attr2, FROM tab2 

where tab2.attr2 not in subQ 

我不想在「不在」之後編寫子選擇符。

Answer 1

正確的SQL使用子查詢：

WITH subQ(attr1) as (
     SELECT attr1 
     FROM tab1 
    ) 
SELECT tab2.attr2 
FROM tab2 
where tab2.attr2 not in (select attr1 from subQ); 

的CTE被視爲一個表的別名，所以應該從from條款引用。

Answer 2

with subQ(attr1) as 
(
    SELECT attr1 FROM tab1 
) 
SELECT tab2.attr2 
FROM tab2 
intersect 
select tab2.attr1 from subQ 

Answer 3

我喜歡NOT EXISTS反而是更清晰，不易出錯：

WITH CTE as 
(
    SELECT attr1 FROM tab1 
) 
SELECT tab2.attr2 FROM tab2 
WHERE NOT EXISTS 
(
    SELECT 1 FROM CTE WHERE CTE.tab1=tab2.attr2 
) 

但是，我沒有看到需要的CTE，在所有。

Should I use NOT IN, OUTER APPLY, LEFT OUTER JOIN, EXCEPT, or NOT EXISTS?