SQL檢查列中的所有值

Question

我在Oracle DB中具有下表。

ID VALUE 
----------- 
1 1 
1 2 
1 3 
2 1 
2 2 
3 1 
3 2 
3 3 
4 1 

如何選擇的ID裏面有所有3個值（1,2,3）

Answer 1

試試這個：

SELECT ID 
    FROM TABLENAME T 
WHERE EXISTS (SELECT * 
       FROM TABLENAME T1 
       WHERE T1.ID = T.ID AND T1.VALUE = '1') 
    AND EXISTS (SELECT * 
       FROM TABLENAME T2 
       WHERE T1.ID = T.ID AND T2.VALUE = '2') 
    AND EXISTS (SELECT * 
       FROM TABLENAME T3 
       WHERE T1.ID = T.ID AND T2.VALUE = '3') 

或

SELECT ID 
    FROM TABLENAME T 
WHERE (SELECT COUNT(*) 
      FROM (SELECT VALUE 
        FROM TABLENAME T1 
       WHERE T1.ID = T.ID 
       GROUP BY VALUE)) = 3; 

，其中3號的值可以通過

 SELECT COUNT(*) 
      FROM TABLENAME T1 
     GROUP BY VALUE 

所以這將是通用：

SELECT ID 
    FROM TABLENAME T 
WHERE (SELECT COUNT(*) 
      FROM (SELECT VALUE 
        FROM TABLENAME T1 
       WHERE T1.ID = T.ID 
       GROUP BY VALUE)) = (SELECT COUNT(*) 
             FROM TABLENAME T2 
            GROUP BY VALUE) 

Answer 2

下面是一個選項... HAVING子句中每個表達式計數被發現等於1，2或3，如果任何值的數量這些計數小於1，那麼ID將不會被返回。

http://sqlfiddle.com/#!4/00fdc/8

SELECT ID 
FROM myTable 
GROUP BY ID 
HAVING 
    SUM(DECODE(VALUE, 1, 1, 0)) > 0 AND 
    SUM(DECODE(VALUE, 2, 1, 0)) > 0 AND 
    SUM(DECODE(VALUE, 3, 1, 0)) > 0 

EDIT - 規定值1，2或3個：

SELECT ID 
FROM myTable 
GROUP BY ID 
HAVING 
    SUM(DECODE(VALUE, 1, 1, 0)) > 0 AND 
    (
     SUM(DECODE(VALUE, 2, 1, 0)) > 0 OR 
     SUM(DECODE(VALUE, 3, 1, 0)) > 0 
) 

Answer 3

從（選擇ID，和（情況下，當值= 1，則1

選擇ID作爲'v1'，
總和（當值= 2然後1其他0結束的情況）作爲'v2'，
總和（當值= 3然後1其他0結束的情況）作爲'v3'
由ID ORAC組）作爲最終
其中，V1> 0且V2> 0和v3> 0

Answer 4

有了這個選項，你會得到更多的比的ID，到你的應用程序選擇您想要的列：

SELECT ID, 
    sum(CASE WHEN VALUE = 1 THEN 1 ELSE 0 END) AS ONE, 
    sum(CASE WHEN VALUE = 2 THEN 1 ELSE 0 END) AS TWO, 
    sum(CASE WHEN VALUE = 3 THEN 1 ELSE 0 END) AS THREE 
FROM MYTABLE 
    GROUP BY ID 
    HAVING ONE >= 1 AND TWO >= 1 AND THREE >= 1; 

或者，如果你的情況是特定的（只值1，2，3是可能的，而且沒有重複值是允許的），那麼你可以嘗試以下操作之一：

SELECT ID, 
    count(VALUE) AS VALUECOUNT 
FROM MYTABLE 
    GROUP BY ID 
    HAVING VALUECOUNT = 3; 

我會以ca重新開始之前，如果您稍後想要添加其他值，則可能會產生副作用。但是，如果您目前的案例符合上述限制條件，仍然值得提出建議。

，當然，如果你不喜歡這些取中間數的想法，我圍內的另一選擇

SELECT ID FROM (
    ... 
) 

Answer 5

最簡單的方式給了查詢一般是這樣的

SQL> ed 
Wrote file afiedt.buf 

    1 with x as (
    2 select 1 id, 1 val from dual union all 
    3 select 1 id, 2 val from dual union all 
    4 select 1 id, 3 val from dual union all 
    5 select 2 id, 1 val from dual union all 
    6 select 2 id, 2 val from dual union all 
    7 select 3 id, 1 val from dual union all 
    8 select 3 id, 2 val from dual union all 
    9 select 3 id, 3 val from dual union all 
10 select 4 id, 1 val from dual 
11 ) 
12 select id 
13 from x 
14 where val in (1,2,3) 
15 group by id 
16* having count(distinct val) = 3 
SQL>/

     ID 
---------- 
     1 
     3 

WHERE子句標識您感興趣的值。HAVING子句告訴您需要存在多少這些值。例如，如果您想要所有具有3個值中的至少2個的行，則會更改HAVING子句以查找COUNT爲2。

如果一個特定的val保證每id最多發生一次，則可以消除HAVING子句中的distinct。