我有一個銷售與領域的表：產品，日期，數量。我需要像這樣提取產品明智的銷售日期格式數據提取一天
Product 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 .............. 31 Total Sale
Rice X X X X X X X X X XX XX XX XX XX XX XX............... XX
Tea X X X X X X X X X XX XX XX XX XX XX XX............... XX
有沒有人有想法如何做到這一點。
您可以使用以下statment在Oracle
SELECT
product
, sum(CASE WHEN TO_CHAR(date, 'dd') = '01' THEN qty ELSE 0 END) as 1
, sum(CASE WHEN TO_CHAR(date, 'dd') = '02' THEN qty ELSE 0 END) as 2
, sum(CASE WHEN TO_CHAR(date, 'dd') = '03' THEN qty ELSE 0 END) as 3
, sum(CASE WHEN TO_CHAR(date, 'dd') = '04' THEN qty ELSE 0 END) as 4
, sum(CASE WHEN TO_CHAR(date, 'dd') = '05' THEN qty ELSE 0 END) as 5
, sum(CASE WHEN TO_CHAR(date, 'dd') = '06' THEN qty ELSE 0 END) as 6
, sum(CASE WHEN TO_CHAR(date, 'dd') = '07' THEN qty ELSE 0 END) as 7
, sum(CASE WHEN TO_CHAR(date, 'dd') = '08' THEN qty ELSE 0 END) as 8
, sum(CASE WHEN TO_CHAR(date, 'dd') = '09' THEN qty ELSE 0 END) as 9
, sum(CASE WHEN TO_CHAR(date, 'dd') = '10' THEN qty ELSE 0 END) as 10
sum(CASE WHEN TO_CHAR(date, 'dd') = '11' THEN qty ELSE 0 END) as 11
, sum(CASE WHEN TO_CHAR(date, 'dd') = '12' THEN qty ELSE 0 END) as 12
, sum(CASE WHEN TO_CHAR(date, 'dd') = '13' THEN qty ELSE 0 END) as 13
, sum(CASE WHEN TO_CHAR(date, 'dd') = '14' THEN qty ELSE 0 END) as 14
, sum(CASE WHEN TO_CHAR(date, 'dd') = '15' THEN qty ELSE 0 END) as 15
, sum(CASE WHEN TO_CHAR(date, 'dd') = '16' THEN qty ELSE 0 END) as 16
, sum(CASE WHEN TO_CHAR(date, 'dd') = '17' THEN qty ELSE 0 END) as 17
, sum(CASE WHEN TO_CHAR(date, 'dd') = '18' THEN qty ELSE 0 END) as 18
, sum(CASE WHEN TO_CHAR(date, 'dd') = '19' THEN qty ELSE 0 END) as 19
, sum(CASE WHEN TO_CHAR(date, 'dd') = '20' THEN qty ELSE 0 END) as 20
sum(CASE WHEN TO_CHAR(date, 'dd') = '21' THEN qty ELSE 0 END) as 21
, sum(CASE WHEN TO_CHAR(date, 'dd') = '22' THEN qty ELSE 0 END) as 22
, sum(CASE WHEN TO_CHAR(date, 'dd') = '23' THEN qty ELSE 0 END) as 23
, sum(CASE WHEN TO_CHAR(date, 'dd') = '24' THEN qty ELSE 0 END) as 24
, sum(CASE WHEN TO_CHAR(date, 'dd') = '25' THEN qty ELSE 0 END) as 25
, sum(CASE WHEN TO_CHAR(date, 'dd') = '26' THEN qty ELSE 0 END) as 26
, sum(CASE WHEN TO_CHAR(date, 'dd') = '27' THEN qty ELSE 0 END) as 27
, sum(CASE WHEN TO_CHAR(date, 'dd') = '28' THEN qty ELSE 0 END) as 28
, sum(CASE WHEN TO_CHAR(date, 'dd') = '29' THEN qty ELSE 0 END) as 29
, sum(CASE WHEN TO_CHAR(date, 'dd') = '30' THEN qty ELSE 0 END) as 30
, sum(CASE WHEN TO_CHAR(date, 'dd') = '31' THEN qty ELSE 0 END) as 31
, sum(qty) as total
FROM
table
group by product
;
以及我的問題已經得到解決，非常感謝所有specialy schurik –
如果月份有30天，該怎麼辦？還是二月？ – armen
嗨schurik如何使用計數功能的情況下，當語句相同的情況下，我想看看多少時間產品銷售日期明智 –
這是你想要的嗎？
SELECT PRODUCT, T_DATE,SUM(QTY)
FROM (SELECT PRODUCT, TRUNC(DATE) T_DATE,QTY
FROM TABLE_NAME)
GROUP BY PRODUCT, T_DATE
ORDER BY PRODUCT
沒有這個查詢不適合我請看我上面的例子 –
你將不得不使用PIVOT，我只把最多6個今日在這裏，包括高達31
WITH base AS (
SELECT product, day(date) AS DAY, sum(qty) AS tot
FROM product GROUP BY product, date)
SELECT product, [1], [2], [3], [4], [5], [6]
FROM base pivot(sum(tot) FOR DAY IN ([1],[2],[3],[4],[5],[6])) as tot;
嘗試 - ：
DECLARE @cols1 NVARCHAR(MAX);
DECLARE @cols2 NVARCHAR(MAX);
DECLARE @sql NVARCHAR(MAX);
DECLARE @myDate DATE;
DECLARE @dNum AS INT;
SET @myDate = '2013-01-01'
SET @dNum = DATEDIFF(DAY, DATEADD(DAY, 1-DAY(@myDate), @myDate), DATEADD(MONTH, 1, DATEADD(DAY, 1-DAY(@myDate), @myDate)))
DROP TABLE ##tttt;
CREATE TABLE ##tttt (
[product] NVARCHAR(20)
, [date] DATETIME
, [quantity] INT
)
INSERT INTO ##tttt ([product], [date], [quantity]) VALUES ('Rice', '2013-01-01', 1)
, ('Rice', '2013-01-02', 5)
, ('Rice', '2013-01-03', 2)
, ('Rice', '2013-01-04', 5)
, ('Rice', '2013-01-05', 3)
, ('Rice', '2013-01-30', 4)
, ('Rice', '2013-01-30', 15)
, ('Rice', '2013-01-30', 1)
, ('Rice', '2013-01-30', 3)
, ('Rice', '2013-01-30', 4)
, ('Tea', '2013-01-01', 1)
, ('Tea', '2013-01-01', 3)
, ('Tea', '2013-01-01', 4)
, ('Tea', '2013-01-01', 1)
, ('Tea', '2013-01-01', 6)
, ('Tea', '2013-01-01', 7)
, ('Tea', '2013-01-03', 2)
, ('Tea', '2013-01-05', 3)
, ('Tea', '2013-01-07', 4)
, ('Tea', '2013-01-08', 7)
, ('Tea', '2013-01-09', 8)
, ('Tea', '2013-01-10', 9)
, ('Tea', '2013-01-21', 1)
, ('Tea', '2013-01-23', 1)
, ('Tea', '2013-01-24', 4)
, ('Tea', '2013-01-31', 10)
, ('Tea', '2014-01-31', 200)
SELECT *
FROM ##tttt
WHERE [date] >= CAST(@myDate AS NVARCHAR(20)) AND [date] < CAST(DATEADD(MONTH, 1, @myDate) AS NVARCHAR(20))
DECLARE @i INT;
SET @i = 1
WHILE @i <= @dNum
BEGIN
SET @cols1 = ISNULL(@cols1, '') + CASE WHEN @i > 1 THEN ',' ELSE '' END + '[' + CASE WHEN LEN(@i) = 1 THEN '0' ELSE '' END + CAST(@i AS NVARCHAR(2)) + ']'
SET @cols2 = ISNULL(@cols2, '') + CASE WHEN @i > 1 THEN ',' ELSE '' END + 'ISNULL([' + CASE WHEN LEN(@i) = 1 THEN '0' ELSE '' END + CAST(@i AS NVARCHAR(2)) + '], 0) AS [' + CASE WHEN LEN(@i) = 1 THEN '0' ELSE '' END + CAST(@i AS NVARCHAR(2)) +']'
SELECT @i = @i + 1;
END;
SET @sql = 'SELECT [product], ' + @cols2 + '
FROM (
SELECT [product], CASE WHEN LEN(DAY([date])) = 1 THEN ''0'' ELSE '''' END + CAST(DAY([date]) AS NVARCHAR(2)) AS day1, [quantity]
FROM ##tttt
WHERE [date] >= ''' + CAST(@myDate AS NVARCHAR(20)) + ''' AND [date] < ''' + CAST(DATEADD(MONTH, 1, @myDate) AS NVARCHAR(20)) + '''
) AS T
PIVOT (
SUM([quantity])
FOR day1 IN (' + @cols1 + ')
) PIVOTTABLE
;'
PRINT @sql
EXEC(@sql)
希望這將幫助你
SELECT *
FROM
(
SELECT productName,
[1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [28], [29],[30], [31]
FROM
(
SELECT productName, day(pDate) AS dayOfDate, sum(quantity) AS Qty
FROM [yourTableName] --Enter here your table name]
WHERE -- Use this to display data for July 2013.
Month(pDate) = 7 and YEAR(pDate) = 2013
GROUP BY productName, day(pDate)
) AS tempTable
PIVOT
(sum(Qty) FOR dayOfDate IN ([1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [28], [29],[30], [31])) as Qty
) AS detailTable,
(
SELECT productName, sum(quantity) as TOTAL
FROM [yourTableName] --Enter here your table name]
WHERE -- Use this to display data for July 2013.
Month(pDate) = 7 and YEAR(pDate) = 2013
GROUP BY productName
) AS totalTable
WHERE totalTable.productName = detailTable.productName
我測試過了它在ADVENTUREWORKS數據庫上。我用下面的查詢：
SELECT *
FROM
(
SELECT productid,
[1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [28], [29],[30], [31]
FROM
(
SELECT productid, day(Modifieddate) AS dayOfDate, sum(Orderqty) AS Qty
FROM Sales.SalesOrderDetail --Enter here your table name
WHERE -- Use this to display data for February 2004.
Month(ModifiedDate) = 2 and YEAR(ModifiedDate) = 2004
GROUP BY productid, day(Modifieddate)
) AS tempTable
PIVOT
(sum(Qty) FOR dayOfDate IN ([1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [28], [29],[30], [31])) as Qty
) AS detailTable,
(
SELECT productid, sum(Orderqty) as TOTAL
FROM Sales.SalesOrderDetail
WHERE -- Use this to display data for February 2004.
Month(ModifiedDate) = 2 and YEAR(ModifiedDate) = 2004
GROUP BY productid
) AS totalTable
WHERE totalTable.ProductID = detailTable.ProductID
請正確的格式在你的問題。這完全是令人困惑的。 –
我們可以在你的餐桌上看到，不僅會導致你需要嗎？ – FSou1
您的問題缺少「給定一個月的一年」 – armen